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Svetlanka [38]
2 years ago
11

Why are high tides found simultaneously on opposite sides of earth?

Physics
1 answer:
dexar [7]2 years ago
7 0

Explanation:

Why are high tides found simultaneously on opposite sides of Earth? The tidal bulges occur on both sides of Earth that are aligned with the tide-generating body. The ocean water experiencing high tide rotates around Earth on a 12-hour cycle.

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Which SI unit is the correctly abbreviated for describing the mass on an object.
djverab [1.8K]
S.I. Unit of mass is Kilogram which is denoted by Kg

In short, Your Answer would be Option C

Hope this helps!
4 0
3 years ago
a boy looks at the reflection of his digital watch in a plane mirror and thinks the time is 10:11. what is the correct time?
Gekata [30.6K]

Answer:

11:10 will be the time. reflection causes the object to be flipped when you see its image at the mirror

6 0
3 years ago
If a piece of an object is dropped down vertically is the moment of inertia gonna be 0? And why?
Degger [83]

Answer:

The object is dropped, we know the initial velocity is zero. Once the object has left contact with whatever held or threw it, the object is in free-fall. Under these circumstances, the motion is one-dimensional and has constant acceleration of magnitude g.

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Explanation:

Hope it helps

5 0
2 years ago
Two remote control cars with masses of 1.16 kilograms and 1.98 kilograms travel toward each other at speeds of 8.64 meters per s
Black_prince [1.1K]

The initial momentum of the system can be expressed as,

p_i=m_1u_1+m_{2_{}}u_2

The final momentum of the system can be given as,

p_f=m_1v_1+m_{2_{}}v_2

According to conservation of momentum,

p_i=p_f

Plug in the known expressions,

\begin{gathered} m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\ m_2v_2=m_1u_1+m_2u_2-m_1v_1 \\ v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2} \end{gathered}

Initially, the second mass move towards the first mass therefore the initial speed of second mass will be taken as negative and the recoil velocity of first mass is also taken as negative.

Plug in the known values,

\begin{gathered} v_2=\frac{(1.16\text{ kg)(8.64 m/s)+(1.98 kg)(-3.34 m/s)-(1.16 kg)(-2.16 m/s)}}{1.98\text{ kg}} \\ =\frac{10.02\text{ kgm/s-}6.61\text{ kgm/s+}2.51\text{ kgm/s}}{1.98\text{ kg}} \\ =\frac{5.92\text{ kgm/s}}{1.98\text{ kg}} \\ \approx2.99\text{ m/s} \end{gathered}

Thus, the final velocity of second mass is 2.99 m/s.

3 0
1 year ago
Between the ball and the player’s head, there are forces. Which of Newton’s laws does this represent? Support your choice.
REY [17]

Answer:

According to Newton's third law

Explanation:

7 0
2 years ago
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