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Juliette [100K]
2 years ago
10

Q/C An undersea earthquake or a landslide can produce an ocean wave of short duration carrying great energy, called a tsunami. W

hen its wavelength is large compared to the ocean depth d, the speed of a water wave is given approximately by v = √(gd). Assume an earthquake occurs all along a tectonic plate boundary running north to south and produces a straight tsunami wave crest moving everywhere to the west. (c) If the wave has amplitude 1.80 m when its speed is 200 m/s, what will be its amplitude where the water is 9.00 m deep?
Physics
1 answer:
iragen [17]2 years ago
7 0

The amplitude A_{2} is 8.307 m

When describing the peak value of a quantity, such as the level of sound waves or the power and voltage in electrical and electronic systems, the term amplitude is employed. A louder sound has a bigger amplitude, and a softer sound has a smaller amplitude.

As we previously discussed in the concept session, the square root of the water's speed is inversely related to the amplitude of its waves.

A\alpha\frac{1}{\sqrt{v} }

Solve for first case:

A_{1}=\frac{1}{\sqrt{v_{1} } }

Solve for second case:

A_{2}=\frac{1}{\sqrt{v_{2} } }

So, the two equations is equal

A^{2} _{1}  v_{1} = A^{2} _{2} v_{2}

        =A^{2} _{2} \sqrt{g d_{2} }

Rearrange and solve for the amplitude A_{2} :

A_{2} =\sqrt{\frac{A^{2}_{1} v_{1} }{v_{2} } }

    =\sqrt{\frac{A^{2}_{1} v_{1}  }{\sqrt{g d_{2} } } }

    =\sqrt{\frac{(1.8m)^{2} X200 m/s }{\sqrt{9.8m/s^{2}X9 m } } }

    = 8.307 m

So, The amplitude A_{2} is 8.307 m.

Learn more about amplitude here:

brainly.com/question/3613222

#SPJ4

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if a bus has a mass of 5000 kg and a velocity of 10 m/s, what must the velocity of a 1500 kg can be to have the same momentum
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6 0
3 years ago
Acceleration is defined as the rate of change for which of the following? Question 4 options: time position velocity displacemen
vovangra [49]

Acceleration can be defined as the rate of change in the velocity of an object. Option C is correct.

<h3>What is Acceleration?</h3>
  • It is defined as the rate of change in velocity.
  • It can also be defined as the rate of change in position in a particular direction.

a =  \dfrac {v-u}t\ \ \ \ \rmor}\\\\a = \dfrac {\Delta v }t

Where,

a - acceleration

\Delta v - change in velocity

t - time

Therefore, acceleration can be defined as the rate of change in the velocity of an object.

Learn more about Velocity:

brainly.com/question/2239252

4 0
2 years ago
A vertical spring withk= 245N/m oscillates with an amplitude of 19.2cm when 0.457kg hangs from it. The mass posses through the e
Makovka662 [10]

Answer:

 y = -19.2 sin (23.15t) cm

Explanation:

The spring mass system is an oscillatory movement that is described by the equation

      y = yo cos (wt + φ)

Let's look for the terms of this equation the amplitude I

     y₀ = 19.2 cm

Angular velocity is

     w = √ (k / m)

     w = √ (245 / 0.457

     w = 23.15 rad / s

The φ phase is determined for the initial condition   t = 0 s ,  the velocity is negative v (0) = -vo

The speed of the equation is obtained by the derivative with respect to time

     v = dy / dt

     v = - y₀ w sin (wt + φ)

For t = 0

     -vo = -yo w sin φ

The angular and linear velocity are related v = w r

      v₀ = w r₀

      v₀ = v₀ sinφ

      sinφ = 1

      φ = sin⁻¹ 1

      φ = π / 4    rad

Let's build the equation

      y = 19.2 cos (23.15 t + π/ 4)

Let's use the trigonometric ratio π/ 4 = 90º

      Cos (a +90) = cos a cos90 - sin a sin sin 90 = 0 - sin a

       y = -19.2 sin (23.15t) cm

8 0
3 years ago
In the diagram, R1 = 40.0 ,
Nostrana [21]

Answer:

51 Ω.

Explanation:

We'll begin by calculating the equivalent resistance of R₁ and R₃. This can be obtained as follow:

Resistor 1 (R₁) = 40 Ω

Resistor 3 (R₃) = 70.8 Ω

Equivalent Resistance of R₁ and R₃ (R₁ₙ₃) =?

Since the two resistors are in parallel connection, their equivalent can be obtained as follow:

R₁ₙ₃ = R₁ × R₃ / R₁ + R₃

R₁ₙ₃ = 40 × 70.8 / 40 + 70.8

R₁ₙ₃ = 2832 / 110.8

R₁ₙ₃ = 25.6 Ω

Finally, we shall determine the equivalent resistance of the group. This can be obtained as follow:

Equivalent Resistance of R₁ and R₃ (R₁ₙ₃) = 25.6 Ω

Resistor 2 (R₂) = 25.4 Ω

Equivalent Resistance (Rₑq) =?

Rₑq = R₁ₙ₃ + R₂ (series connection)

Rₑq = 25.6 + 25.4

Rₑq = 51 Ω

Therefore, the equivalent resistance of the group is 51 Ω.

4 0
3 years ago
What is the speed of an object traveling a distance of 25 meters in 25 seconds
sergeinik [125]

Answer:

1 meter per second

Explanation:

Speed=Distance/Time

S=D/T

S=25/25

S=1

6 0
3 years ago
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