What would be the best way for her to do this?

Help please <br>the question is in the picture

zavuch27 [327]

Answer:

The SI unit of power is the watt

Explanation:

7 0

3 years ago

Read 2 more answers

Calculate the acceleration of a 1400-kg car that stops from 39 km/h "on a dime" (on a distance of 1.7 cm).

Vinil7 [7]

Answer:

$a=-3449.67\frac{m}{s^2}$

Explanation:

The car is under an uniforly accelerated motion. So, we use the kinematic equations. We calculate the acceleration from the following equation:

$v_f^2=v_0^2+2ax$

We convert the initial speed to $\frac{m}{s}$

$39\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=10.83\frac{m}{s}$

The car stops, so its final speed is zero. Solving for a:

$a=\frac{v_0^2}{2x}\\a=-\frac{(10.83\frac{m}{s})^2}{2(1.7*10^{-2}m)}\\a=-3449.67\frac{m}{s^2}$

4 0

3 years ago

a rocket is launched with a constant acceleration straight up. exactly 4.00 seconds after lift off, a bolt falls off the side of

Papessa [141]

The initial speed of the bolt is not 58.86 m/s.

Let a be the acceleration of the rocket.

During the 4 sec lift off, the rocket has reached a height of

h = (1/2)*a*t^2

with t=4,

h = (1/2)*a^16

h = 8*a

Its velocity at 4 sec is

v = t*a

v = 4*a

The initial velocity of the bolt is thus 4*a.

During the 6 sec fall, the bolt has the initial velocity V0=-4*a and it drops a total height of h=8*a. From the equation of motion,

h = (1/2)*g*t^2 + V0*t

Substituting h0=8*a, t=6 and V0=-4*a into it,

8*a = (1/2)*g*36 - 4*a*6

Solving for a

a = 5.52 m/s^2

6 0

3 years ago

The standard measure used to compare sound intensity is the_____

BartSMP [9]

Frequency? Possibly I’m not 100% sure

5 0

3 years ago

Astronaut Rob leaves Earth in a spaceship at a speed of 0.960crelative to an observer onEarth. Rob's destination is a star syste

Slav-nsk [51]

To solve this problem we will use the mathematical definition of the light years in metric terms, from there, through the kinematic equations of motion we will find the distance traveled as a function of the speed in proportion to the elapsed time. Therefore we have to

$1Ly =9.4605284*10^{15}m \rightarrow 'Ly'$ means Light Year