We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.

We know that formula for permutations is given as

On substituting the given values in the formula we get,


Therefore, there are 39270 ways in which prizes can be awarded.
Answer:
2.99m-4 (less than or equal to symbol after) 20
Step-by-step explanation:
This would come out too 5 movies because 20-4= 16 16-2.99=5.3 but it is impossible to buy 5.3 movies so you would round it down to 5
Answer: 1/8
<u>Step-by-step explanation:</u>
First Bag and Second Bag
x
=
which reduces to 
Answer : A and C have the same value
I hope that's help !