The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
10-3=N
N=7
Step-by-step explanation:
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Answer:
- max: 28.5 inches
- min: 27.5 inches
Step-by-step explanation:
If the actual dimension were different from 28 inches by more than 1/2 inch, it would be reported as a different dimension. So, the minimum that will be reported as 28 is 27.5. The maximum that will be reported as 28 will be 28.4999999.... ≈ 28.5
The maximum and minimum length of the sheet are 28.5 inches and 27.5 inches, respectively.
Answer: 2 per month
8 per four months
Step-by-step explanation:
The solution for the given equations x + 3y = 5 and x - 3y = -1 are x=2 and y=1.
Step-by-step explanation:
The given is,
......................................(1)
....................................(2)
Step:1
By elimination method,
Subtracting Equations (1) and (2),
( - )
( 
) + ( 
) = ( 
)
= 6
= 1
Step:2
Substitute the value of y in equation (1),
+ ( 3 × 1 ) = 5
= 5-3
= 2
Step:3
Check for Solution,
Substitute the values of x and y in Eqn (1),
2 + ( 3 × 1 ) = 5
5 = 5
Result:
The solution for the given equations x + 3y = 5 and x - 3y = -1 are x=2 and y=1, by elimination method.
