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2 years ago

Square root of 119 with work

Mathematics

2 answers:

sammy [17]2 years ago

6 0

√119 ≈ 10.908712115

NeTakaya2 years ago

6 0

Answer:

This can't really be broken down, so you would either write the answer as the question, or put it in decimal form.

So the choices would be:

$\sqrt{119}$ or 10.9

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A community swimming pool is a rectangular prism that is 30 feet long, 12 feet wide, and 5 feet deep. The wading pool is half as

topjm [15]

Answer:

The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.

Step-by-step explanation:

By definition of rectangular prism, we get the respective formulas for the volumes of the community swimming pool and the wadling pool, respectively:

Community swimming pool

$V_{c} = l\cdot w\cdot h (1)$

Wading pool

$V_{w} = \left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w (2)$

Where:

l – Length of the swimming pool, measured in feet.

h – Depth of the swimming pool, measured in feet.

w – Width of the swimming pool, measured in feet.

$V_{c}$ – Volume of the community swimming pool, measured in cubic feet.

$V_{w}$ – Volume of the wading swimming pool, measured in cubic feet.

The ratio of the volume of the community swimming pool to the volume of the wadling pool is:

$\frac{V_{c}}{V_{w}} = \frac{l\cdot w \cdot h}{\left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w} (3)$

$\frac{V_{c}}{V_{w}} = \frac{1}{\frac{1}{4} }$

$\frac{V_{c}}{V_{w}} = 4$

The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.

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1 year ago

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The measure of angle A is 15°, and the length of side

dangina [55]

Answer:

Part 1) $AB=30.9\ units$

Part 2) $AC=29.9\ units$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

$sin(A)=\frac{BC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(15^o)=\frac{8}{AB}$

solve for AB

$AB=\frac{8}{sin(15^o)}=30.9\ units$

Part 2

Find the length side AC

we know that

$tan(A)=\frac{BC}{AC}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

$tan(15^o)=\frac{8}{AC}$

solve for AC

$AC=\frac{8}{tan(15^o)}=29.9\ units$

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Answer: Adjacent Angles

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seraphim [82]

i think its 3√3 because that seems like the logical answer to me.

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