Answer:
paper = $4 and stapler = $7
Step-by-step explanation:
let p represent paper and s represent stapler, then
3p + 4s = 40 → (1)
5p + 6s = 62 → (2)
Multiplying (1) by 5 and (2) by - 3 and adding will eliminate p
15p + 20s = 200 → (3)
- 15p - 18s = - 186 → (4)
Add (3) and (4) term by term to eliminate p
2s = 14 ( divide both sides by 2 )
s = 7
Substitute s = 7 into either of the 2 equations and evaluate for p
Substituting into (1)
3p + 4(7) = 40
3p + 28 = 40 ( subtract 28 from both sides )
3p = 12 ( divide both sides by 3 )
p = 4
Thus package of paper costs $4 and stapler costs $7
Solution :
Given :
Principal amount deposited, P = $ 6000
Rate of interest, r = 5%
Number of years, t = 4 years
When the deposited amount is compounded semiannually, i.e. n = 2
Therefore,
Future value,



= 6000 x 1.2184
= 7310.4
Therefore, after 4 years there will be $ 7310.4 in the amount when compounded semi annually.
When the deposited amount is compounded quarterly, i.e. n = 4
Therefore,
Future value,



= 6000 x 1.219889
= 7319.334
Therefore, after 4 years there will be $ 7319.334 in the amount when compounded quarterly.
When the deposited amount is compounded monthly, i.e. n = 12
Therefore,
Future value,



= 6000 x 1.22089
= 7325.34
Therefore, after 4 years there will be $ 7325.34 in the amount when compounded monthly.
Answer:
the soda's are one$
and the snacks are three$
Answer:
Step-by-step explanation:
Is C