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3 years ago

Help me pls I need this by today

Mathematics

1 answer:

asambeis [7]3 years ago

4 0

Answer: r=0.4 its a guess but i dont think thats a negitive slope it looks positive so :P

Step-by-step explanation:

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The manager of a supermarket wants to obtain information about the proportion of customers who dislike a new policy on cashing c

alex41 [277]

Answer:

n = 61 costumers

Step-by-step explanation:

For calculating the number of costumers he should sample we use the next equation:

$n = \frac{z_{1-\alpha/2}^{2}p(1-p)}{E^{2} }$

Where E is the error that we are prepared to accept, in this case E = 0.15

How we don't know the value of p, we can estimate it like p = 0.5

∝ = 1-0.98 = 0.02

1-∝/2 = 0.99

$z_{0.99} = 2.33$

$n = \frac{(2.33^{2})(0.5)(1-0.5)}{0.15^{2} }$

n = 60.32 costumers

n ≈ 61 costumers

4 0

3 years ago

What is the answer to -8 = 2x

galina1969 [7]

Answer:

Step-by-step explanation:

-4

3 0

3 years ago

Read 2 more answers

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

An exponential growth function has an asymptote of y = –3. Which might have occurred in the original function to permit the rang

Blababa [14]

The right choice is: A whole number constant could have been subtracted from the exponential expression.

Let be an exponential function of the form $y = A\cdot e^{B\cdot x}$ , where $A$ and $B$ are real numbers. A horizontal asymptote exists when $e^{B\cdot x} \to 0$ , which occurs for $B\cdot x \to - \infty$ .

For this function, the horizontal asymptote is represented by $y = 0$ and to change the value of the asymptote we must add the parent function by another real number ( $C$ ), that is to say:

$y = A\cdot e^{B\cdot x} + C$ (1)

In this case, we must use $C = -3$ to obtain an horizontal asymptote of -3. Thus, the right choice is: A whole number constant could have been subtracted from the exponential expression.

To learn more on asymptotes, we kindly invite to check this verified question: brainly.com/question/8493280

3 0

2 years ago

Read 2 more answers

Conversión a fracción de 0.355

Likurg_2 [28]

335/1000 if you read it out loud .335 is three hundred fifty-five thousandths

3 0

3 years ago