A pentagon can be divided into how many triangles by drawing all of the diagonals from one vertex? A. 5 B. 4 C. 2 D. 3

Mathematics

2 answers:

timama [110]3 years ago

7 0

The correct answer is D

Hope it helps

<3

shusha [124]3 years ago

3 0

D. 3 since one vertex always face 2 vertex that you can draw a diagonal line with, its going to divide the pentagon to 3 different area which form 3 triangles

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3 years ago

Consider the expression. (StartFraction 2 m Superscript negative 1 baseline n Superscript 5 Baseline Over 3 m Superscript 0 Base

suter [353]

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The correct option is option (3) 4 ÷ 25.

Step-by-step explanation:

The expression in terms of m and n is:

$F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}$

Exponent rule of division:

$a^{x}\div a^{y}=a^{x-y}$

Compute the value of the expression for m = -5 and n = 3 as follows:

$F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}$

$F(-5,3)=[\frac{2\csdot (-5)^{-1}\cdot (3)^{5}}{3\cdot (-5)^{0}\cdot (3)^{4}}]^{2}$

$=\{\frac{2}{3}\times [(-5)^{-1-0}\times (3)^{5-4}}]\}^{2}\\\\=\{\frac{2}{3}\times \frac{-1}{5}\times 3\}^{2}\\\\=\{-\frac{2}{5}\}^{2}\\\\=\frac{4}{25}$