Answer:
Step-by-step explanation:
150 is the answer I need these points
The equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
<h3>Equation of a line</h3>
A line is the shortest distance between two points. The equation of a line in point-slope form and perpendicular to a line is given as;
y - y1 = -1/m(x-x1)
where
m is the slope
(x1, y1) is the intercept
Given the following
Point = (4, -1)
Line: 2x-y - 7 = 0
Determine the slope
-y = -2x + 7
y= 2x - 7
Slope = 2
Substitute
y+1 = -1/2(x -4)
Write in slope-intercept form
2(y + 1) = -(x - 4)
2y+2 = -x + 4
2y = -x + 2
y = -1/2 + 1
Hence the equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
Learn more on equation of a line here: brainly.com/question/13763238
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Answer:
17. a)
Step-by-step explanation:
17.
f(x) =x/2, then f(x-3)=(x-3)/2
x=3, f(x-3)=f(3-3)=f(0)=0 (values in table)
f(x-3)+3=0+3=3
18.
f(x) =x/2
f(x-2) for x=5 is f(5-2)=f(3)=3/2
f(x-2)+5=f(3)+5=3/2+5=3/2+10/2=13/2
