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Lunna [17]
3 years ago
14

Your company shares a building with a competitor's branch office. Recently, you noticed that some computers other than company c

omputer have tried to connect to the wireless network unsuccessfully. When you are in the parking lot, you also notice that the company's wireless network SSID can be seen on your smartphone.What can you do to make sure no one outside your company can gain access to its wireless network?
Computers and Technology
1 answer:
professor190 [17]3 years ago
5 0

<u>The wireless network:</u>

Wireless networking and internet access are essentials when it comes to the smooth functioning of an enterprise. Certain information can be transferred from one computer to another within a specified if they are connected to a network.

In this case, as the company shares the building with the branch office of a rival company there may be repercussions. First of all, the company's wireless network should be equipped with a strong password and it should be changed regularly too.

Next, the officials responsible for networking should also monitor the range of their wireless network. There is no point in keeping the range of wireless network wide as it is to be used by employees only and they can access it on the company's premises.

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5 0
3 years ago
Write a function which the counts the number of odd numbers and even numbers currently in the stack and prints the results.
Lerok [7]

Answer:

See the code below and the algorithm explanation on the figure.

Explanation:

The explanation in order to get the answer is given on the figure below.

Solving this problem with C. The program is given below:

#include <stdio.h>

int main(void) {

   int n, Even=0, Odd=0, Zeros=0;  

   for (;;) {

       printf("\nEnter the value the value that you want to check(remember just integers): ");

       //IF we input a non-numeric character the code end;

       if (scanf("%d", &n) != 1) break;

       if (n == 0) {

           Zeros++;

       }

       else {

           if (n % 2) {

               Even++;

           }

           else {

               Odd++;

           }

       }

   }  

   printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);

   return 0;

}

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