Ask question

Ask question

All categories

kakasveta [241]

3 years ago

14

Osmotic pressure is created by the presence in a fluid of small diffusible molecules that easily move through the capillary memb

rane. Osmotic pressure is created by the presence in a fluid of small diffusible molecules that easily move through the capillary membrane. True False

1 answer:

Montano1993 [528]3 years ago

6 0

Answer:

False

Explanation:

When solutions of different concentration are placed, separated by a semipermeable membrane, the molecules pass from the solution with the lowest concentration of solutes to the one with the highest concentration. This generates a pressure difference on both sides of the semipermeable membrane, called osmotic pressure.

You might be interested in

Divers found two substances on the bottom of the ocean. At room temperature, both substances are liquid. Scientists then transfe

e-lub [12.9K]

Answer:

Substance 2 is a still figure and substance 1 isn't

Explanation:

5 0

2 years ago

Read 2 more answers

A Huge water tank is 2m above the ground if the water level on it is 4.9m high and a small opening is there at the bottom then t

lapo4ka [179]

Answer:

The speed of efflux of non-viscous water through the opening will be approximately 6.263 meters per second.

Explanation:

Let assume the existence of a line of current between the water tank and the ground and, hence, the absence of heat and work interactions throughout the system. If water is approximately at rest at water tank and at atmospheric pressure ( $P_{atm}$ ), then speed of efflux of the non-viscous water is modelled after the Bernoulli's Principle:

$P_{1} + \rho\cdot \frac{v_{1}^{2}}{2} + \rho\cdot g \cdot z_{1} = P_{2} + \rho\cdot \frac{v_{2}^{2}}{2} + \rho\cdot g \cdot z_{2}$

Where:

$P_{1}$ , $P_{2}$ - Water total pressures inside the tank and at ground level, measured in pascals.

$\rho$ - Water density, measured in kilograms per cubic meter.

$g$ - Gravitational acceleration, measured in meters per square second.

$v_{1}$ , $v_{2}$ - Water speeds inside the tank and at the ground level, measured in meters per second.

$z_{1}$ , $z_{2}$ - Heights of the tank and ground level, measured in meters.

Given that $P_{1} = P_{2} = P_{atm}$ , $\rho = 1000\,\frac{kg}{m^{3}}$ , $g = 9.807\,\frac{m}{s^{2}}$ , $v_{1} = 0\,\frac{m}{s}$ , $z_{1} = 6.9\,m$ and $z_{2} = 4.9\,m$ , the expression is reduced to this:

$\left(9.807\,\frac{m}{s^{2}} \right)\cdot (6.9\,m) = \frac{v_{2}^{2}}{2} + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.9\,m)$

And final speed is now calculated after clearing it:

$v_{2} = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (6.9\,m-4.9\,m)}$

$v_{2} \approx 6.263\,\frac{m}{s}$

The speed of efflux of non-viscous water through the opening will be approximately 6.263 meters per second.

5 0

4 years ago

A steam stream of 400 m3 /s, standard (standard cubic meter per second) is cooled by adding 7 m3 /s cold water. The fluid leavin

antiseptic1488 [7]

Answer: 510 m/s

Explanation: specific gravity of steam is 18/29 = 0.620

It is the ratio of the density of steam over density of water

400m3/s of steam =

400m3ms * 0.620 of water

= 248m3/s of water

Total flow rate Q = 248 + 7 = 255m3/s

Using Q = AV

Where A is area and V is velocity

V = Q/A

V = 255/0.5 = 510m/s

4 0

3 years ago

according to the law of conservation of energy the total amount of energy in the universe does not change but remains constant t

allsm [11]

True hope this helps

7 0

3 years ago

Using two spring scales, students pull on opposite sides of a dynamic cart at rest. 7 Newtons of force is pulling left and 5 New

kirill [66]

Answer:

The cart will accelerate to the left

Explanation:

The cart is initially at rest. In order to understand its motion, we should consider the net force acting on the cart. We have two forces acting on it:

- A force of 7 N to the left

- A force of 5 N to the right

Therefore, the net force is

$F=7 N -5N=2 N$

in the direction of the stronger force (so, to the left).

According to Newton's second law:

$F=ma$

a net force different from zero produces an acceleration of the object, in the same direction as the net force. Therefore, the cart will accelerate to the left.

7 0

3 years ago