Answer:
Explanation:
Llya and anya run speed is 7.7mph
Anya and play walk speed is 4mph
They want to travel a total distance of 5miles
Anya walks half of the journey and run half of the journey
Llya walks half of the time and runs half of the time.
A. How long does it take Anya to cover the distance of 5.00 miles?
Since anya walk half which is 2.5miles
So, she runs half which is 2.5 miles
Speed is given as distance /time
S=d/t
Therefore walking time us
t=d/S., d=2.5mile and S=4mph
t=2.5/4
t=0.625h
The running time
t=d/S. d =2.5mile and S=7.7mph
t=2.5/7
t=0.357h
Total time is 0.625+0.357
t=1.007hour
B. Average speed of anya
Average speed is given by total distance travel over total time traveled
A.S=total distance/time
Total distance is 5mile and time =1.007h
A.S=5/1.007
A.S=4.96mph
A.s=4.96miles/hour
C. How long does it take Ilya to cover the distance?
Let the total time llya use to travel be t
Then walk time =0.5t
Running time =0.5t
Total distance travel is 5miles
Total distance = speed ran × time ran + speed walked × time walked
5=7.7×0.5t+4×0.5t
5=3.85t+2t
5=5.85t
Then, t=5/5.85
t=0.855h.
D. Llya average speed
Average speed is given by total distance travel over total time traveled
A.S=total distance/total time
A.S=5/0.855
A.S=5.85mph
