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Gnoma [55]
3 years ago
5

Identify the GCF of the following terms: 40a5b9c4and 22a7b6

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0

Answer:

Check photo.

Step-by-step explanation:

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Evaluate the expression when b= 3 and c = -4 <br><br>b - 4c ​
Sedaia [141]

Answer:

15.

c is a negative

3 - (-12)

15

5 0
3 years ago
in circle F, points A,B,C,D, and E are located on the circle such that measure of C=119°, and BE is perpendicular AD. determine
VLD [36.1K]

Answer:

Measure of arc AE = 58°

Step-by-step explanation:

As shown: ABCD is a quadrilateral, ∠C = 119°

So, ∠C + ∠A = 180°

∴ ∠A = 180° - ∠C = 180° - 119° = 61°

ΔAGB is a right triangle at G

So, ∠A + ∠B = 90°

∴ ∠ABG = 90 - ∠A = 90 - 61 = 29°

Arc AE opposite to the angle ∠ABG

So, measure of arc AE = 2∠ABG = 2 * 29° = 58°

6 0
4 years ago
The Table Shows The Number Of Rows Of Bricks A Worker Can Lay In Different Numbers Of Hours
klemol [59]
The answer is 3. If you set it up in a T table and label x as the number of hours and y as the number of rows. Then use rise over run (y over x) the fractions simplify to 3 over 1.
4 0
3 years ago
Goldie's apple juice boxes hold 6.9 ounces. If there are 8 boxes in a package, how many ounces of apple juice are in a package?
yuradex [85]
Answer:

See below

Explanation:

You multiply 8 and 6.9
To get 55.2 ounces
6 0
2 years ago
En la división sintética sólo son tomados en cuenta los coeficientes del divisor?
Airida [17]

La división sintetica sirve para el cociente entre polinomios, la cual es particularmente util para cuando tenemos un numerador de grado alto y un denominador de grado 1.

Veremos que si, en la división sintética solo son tomados en cuenta los coeficientes del divisor.

Para explicarla, usaremos un ejemplo.

x^3 - 2x^2 + 5x + 3  será el <u>numerador</u>

x - 2 será el <u>denominador.</u>

Para poder aplicar la división sintetica, el maximo exponente en el <u>denominador </u>debe ser uno.

Así, nuestro cociente es:

\frac{x^3 - 2x^2 + 5x + 3}{x-2}

Procedemos a igualar el <u>denominador</u> a cero:

x - 2 = 0

x = 2

Ahora veremos los coeficientes del <u>numerador</u> (el <u>numerador </u>es el <u>divisor</u>).

Lo que debemos hacer es tomar cada coeficiente (comenzando por los que multiplican a los terminos con mayor exponente) y multiplicarlos por este número.

En este caso, el primer coeficiente es 1.

2*1 = 2

Ahora le sumamos esto al proximo coeficiente, que es -2:

-2 + 2 = 0

Multiplicamos esto por el valor de x, que es 2.

2*0 = 0

Ahora sumamos esto al proximo coeficiente, que es 5

5 + 0  = 5

Multiplicamos esto por el valor de x, que es 2:

5*2 = 10

Sumamos esto al ultimo coeficiente, que es 3.

10 + 3 = 13

Este ultimo valor es el residuo, y los primeros 3 números que obtuvimos son los coeficientes del cociente, entonces el cociente será:

1*x^2 + 0*x + 10 = x^2 + 10

Como vimos, solo usamos los coeficientes del numerador/divisor para realizar esta operación, por lo que si, solo los coeficientes del divisor son tomados en cuenta.

Si quieres aprender más, puedes leer:

brainly.com/question/10466403

3 0
3 years ago
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