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Zigmanuir [339]
3 years ago
15

3. What is the value of x? (8x -- 8) (7x - 8) A -16 B. 120 C. 60 D. 16

Mathematics
1 answer:
hram777 [196]3 years ago
3 0

Answer:

16

Step-by-step explanation:

took test

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The cost, C. of producing coolers, x, is modeled by the equation C = 0.005x2 - 0.3x + 17. How many coolers are
melamori03 [73]

Answer:

66 coolers

Step-by-step explanation:

C = 0.005x² - 0.3x + 17

When C = $19

19 = 0.005x² - 0.3x + 17

19 - 17 = 0.005x² - 0.3x

2 = 0.005x² - 0.3x

0.005x² - 0.3x - 2 = 0

x = -b ± √b² - 4ac / 2a

= -(-0.3) ± √-0.3² - 4*0.005*-2 / 2*0.005

= 0.3 ± √ 0.09 - (-0.04) / 0.01

= 0.3 ± √ 0.09 + 0.04 / 0.01

= 0.3 ± √ 0.13 / 0.01

= 0.3/0.01 ± √0.13/0.01

= 30 ± 0.36/0.01

x = 30 ± 36

x = 30 + 36 or 30 - 36

x = 66 or -6

Number of coolers can not be negative

Therefore, number of coolers produced when the cost is $19

is 66 coolers

3 0
2 years ago
A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte
ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, q_1 = Q- r \times Q

q_1 = Q(1-r)\cdots(i)

The value of quantity after 2 months, q_2 = q_1- r \times q_1

q_2 = q_1(1-r)

From equation (i)

q_2=Q(1-r)(1-r)  \\\\q_2=Q(1-r)^2\cdots(ii)

The value of quantity after 3 months, q_3 = q_2- r \times q_2

q_3 = q_2(1-r)

From equation (ii)

q_3=Q(1-r)^2(1-r)

q_3=Q(1-r)^3

Similarly, the value of quantity after n months,

q_n= Q(1- r)^n

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

q_{48}=Q(1-r)^{48}

Putting Q=6200 and r=5.5%=0.055, we have

q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32

Hence, the value of quantity after 4 years is 410.32.

4 0
2 years ago
Read 2 more answers
Which classification describes the following system of equations? inconsistent and dependent consistent and dependent consistent
sveta [45]

The system of equations is consistent and independent and the solutions are x = 4, y = 5, and z = -1 option third is correct.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have three linear equations in three variables:

x - y - z = 0 ..(1)

2x - y + 2z = 1 ..(2)

x - y + z = -2 ..(3)

From the equation (1):

\rm x=y+z

Plug this value in the equation (2) and (3):

\rm 2\left(y+z\right)-y+2z=1\\\\ y+z-y+z=-2

After solving we get:

z = -1

y = 5

Plug the above two values in equation (1) we get:

x = 4

Thus, the system of equations is consistent and independent and the solutions are x = 4, y = 5, and z = -1 option third is correct.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

5 0
1 year ago
Checking account A charged a monthly fee of $5 and a per-check fee of $0.25, and checking account B charged a monthly fee of $6
Genrish500 [490]
First we need to know both the formula of A and B.

The formula of A is
C = 5 + 0.25p
with C representing total cost and p representing the amount of checks.

The formula of B is
C = 6 + 0.15p
with C representing total cost and p representing the amount of checks.

To find the point where A and B cost the same, we solve the following equation:
5 + 0.25p = 6 + 0.15p

Collecting terms gives us
-1 = -0.1p

Now we have to divide by -0.1 and we get.
10 = p
p = 10

So our answer: after 10 checks both accounts cost the same amount of money. Answer A.
7 0
2 years ago
Evaluate the expression when m = -8.6 and n = -2.7. <br> -7n+4m
Sunny_sXe [5.5K]

Answer:

-15.5

Step-by-step explanation:

-7(-2.7)+4(-8.6)=-15.5

18.9-34.4=-15.5

5 0
3 years ago
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