Let's take a look at the first few numbers in the sequence based on the given rule:
Inspecting this pattern it seems like the power
is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be
. We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as
Where
is the nth number in our sequence.
Answer:
1. ![(\sqrt[5]{(m+2)})^{3} = (m+2)^{\frac{3}{5}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7B%28m%2B2%29%7D%29%5E%7B3%7D%20%3D%20%20%28m%2B2%29%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D)
2. ![(\sqrt[3]{(m+2)})^{5} = (m+2)^{\frac{5}{3}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B%28m%2B2%29%7D%29%5E%7B5%7D%20%3D%20%20%28m%2B2%29%5E%7B%5Cfrac%7B5%7D%7B3%7D%7D)
3. ![\sqrt[5]{(m)}^{3}+2 = m^{\frac{3}{5}}+2](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B%28m%29%7D%5E%7B3%7D%2B2%20%3D%20%20m%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D%2B2)
4. ![\sqrt[3]{(m)}^{5}+2 = m^{\frac{5}{3}}+2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28m%29%7D%5E%7B5%7D%2B2%20%3D%20%20m%5E%7B%5Cfrac%7B5%7D%7B3%7D%7D%2B2)
Step-by-step explanation:
Recall that
![(\sqrt[n]{x})^{m} = (x^{\frac{m}{n}})](https://tex.z-dn.net/?f=%28%5Csqrt%5Bn%5D%7Bx%7D%29%5E%7Bm%7D%20%3D%20%20%28x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%29)
Where 
is called radicand and n is called index
1. Root(5, (m + 2) ^ 3)
In this case,
n is 5
m is 3
x = (m + 2)
2. Root(3, (m + 2) ^ 5)
In this case,
n is 3
m is 5
x = (m + 2)
3. Root(5, m ^ 3) + 2
In this case,
n is 5
m is 3
x = m
4. Root(3, m ^ 5) + 2
In this case,
n is 3
m is 5
x = m
A, B and D are your answers according to e2020
Answer: So Kate has 2/3 yard is fabric which is equal to 24 inches and if each flag requires 1/6 yards of fabric it would equal 12 inches. So all in all Kate can make 2 flags. Hope that helped.
Step-by-step explanation:
6 because 6X6=36 and a square has all sides equal.
