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andreyandreev [35.5K]
3 years ago
15

Certain arithmetic sequence has the recursive formula an = an-1 + d

Mathematics
1 answer:
Liula [17]3 years ago
4 0
The formula is an = 1+d
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Find a unit vector in the same direction as the given vector: v = −14.5i + 2.5 j.
Elis [28]

ANSWER

-  \frac{29}{866}  \sqrt{866} i + \frac{5}{866}  \sqrt{866} j

EXPLANATION

The given vector is v = −14.5i + 2.5 j.

The magnitude of this vector is

|v|  =  \sqrt{ {( - 14.5)}^{2}  +  {2.5}^{2} }

v|  =  \sqrt{ {( - 14.5)}^{2}  +  {2.5}^{2} }

v|  =  \sqrt{ 216.5}  =  \frac{ \sqrt{866} }{2}

The unit vector in the direction of this vector is

=  \frac{v}{ |v| }

= -   \frac{14.5}{ \frac{ \sqrt{866} }{2} } i +    \frac{2.5}{ \frac{ \sqrt{866} }{2} } j

=  -  \frac{29}{866}  \sqrt{866} i + \frac{5}{866}  \sqrt{866} j

7 0
3 years ago
What is equivalent to 4/9(2n-3)
sp2606 [1]
4/9(2n)+4/9(-3)
(4x2/9)n+(4 x -3)/9
(8/9)n -12/9
8/9n-4/3
4 0
2 years ago
Graph the system of equations on your graph paper to answer the question.
scZoUnD [109]
<span>y=x-4
y=-x+6 
---------------------
Substitute x - 4 for y in </span>y=-x+6 
x-4=-x+6<span>
--------------------------------
Add X on each side
</span><span>x-4+x</span>=-<span>x+6+x
</span>2x - 4 = 6
--------------------------------------
Add 4 on each side
<span>2x-4+4</span>=<span>6+4
</span>2x = 10
------------------------------------------------
Divide by 2 on each side
2x ÷ 2 = 10 ÷ 2
x = 5
Now we have X
================================================================
To find Y we substitute 5 for x in y=<span>x-<span>4
</span></span>y = 5 - 4
y = 1
-----------------------------------------------------
Your answers are Y = 1 and X = 5

8 0
3 years ago
What is the range of f(x) = 3x + 9?
Shkiper50 [21]
The answer is 2 i think

3 0
3 years ago
Read 2 more answers
Is the following relation a function?<br><br> A. Yes<br> B. No
SVETLANKA909090 [29]

Answer:

  B.  No

Step-by-step explanation:

In order for the relation to be a function, each X value must source exactly one arrow. The value -1 maps to two different values (2, -1), so the relation is NOT A FUNCTION.

3 0
2 years ago
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