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Here, we are required to find the area of the paper board given after the semicircle is cut out of it
Area of the paper board thatremains is 423 in²
Length = 29 in
Width = 20 in
Area of a rectangle = length × width
= 29 in × 20 in
= 580 in²
Area of a semi circle = πr²/2
π = 3.14
r = diameter / 2 = 20 in / 2 = 10 in
Area of a semi circle = πr²/2
= 3.14 × (10 in)² / 2
= 3.14 × 100 in² / 2
= 314 in²/2
= 157 in²
The semicircle is cut out of the rectangle
Find the area of the paper board that remains after the semicircle is cut out of it by subtracting the area of a semi circle from the area of a rectangle
Area of the paper board that remains = Area of a rectangle - Area of a semi circle
= 580 in² - 157 in²
= 423 in²
brainly.com/question/16994941
Answer: the length is 87 feet
The width is 40 feet
Step-by-step explanation:
Let L represent the length of the playing field.
Let W represent the width of the playing field.
The playing field is rectangular. The formula for determining the perimeter of a rectangle is expressed as
Perimeter = 2(L + W)
The perimeter of a playing field for a certain sport is 254 ft. This means that
254 = 2(L + W)
L + W = 254/2
L + W = 127 - - - - - - - - - - - -1
The length is 47 ft longer than the width. This means that
L = W + 47
Substituting L = W + 47 into equation 1, it becomes
W + 47 + W = 127
2W + 47 = 127
2W = 127 - 47 = 80
W = 80/2 = 40
L = W + 47 = 40 + 47
L = 87
Estimation:
23 --> rounded to 20
71 --> rounded to 70
70 + 20 = 90. I rounded both numbers down so the exact sum must be only a little greater than my estimate.
Answer:
B
Step-by-step explanation:
To go from 6 to 9 you'd first have to divide 6 by 2 and the multiply by 3,
so 
x 3 = 
