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den301095 [7]
3 years ago
11

Tina pet sits to earn extra money. She charges a flat service fee of $20, plus $20 per day. If one of her customers spent less t

han $80, which of the following inequalities could be used to solve for x, the number of days the customer paid for pet sitting?a) $20x + $20 < $80b) $20x < $80c) $20x - $20 < $80d) $20x < $100
Mathematics
1 answer:
Sloan [31]3 years ago
3 0

Answer:option A is the correct answer.

Step-by-step explanation:

Let x represent the number of days the customer paid for pet sitting.

She charges a flat service fee of $20, plus $20 per day. This means that the total amount that she charges for x hours would be

20 + 20x

If one of her customers spent less than $80, then the inequality that could be used to solve for x would be

$20 + $20x < $80

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A line has a slope of 2. Write an equation in slope intercept form for the line that is perpendicular to this line.
notsponge [240]

Hey there!

A perpendicular line's slope to another line is always the negative reciprocal of slope.

If our line has a slope of two, we first must find the reciprocal, which is 1/2. Then, we put a negative on it.

Therefore, our equation is y=-1/2x+b.

I hope that this helps! Have a great day!

6 0
3 years ago
Read 2 more answers
Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu
kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

f(x) =  {x}^{5}  -  {x}^{3}  + 6

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

f'(x) = 5 {x}^{4} - 3 {x}^{2}

At turning point f'(x)=0.

5 {x}^{4} - 3 {x}^{2}  = 0

This implies that,

{x}^{2} (5 {x}^{2}  - 3) = 0

{x}^{2}  = 0 \: or \: 5 {x}^{2}  - 3 = 0

x =  - \frac{ \sqrt{15} }{5}   \: or \: x = 0 \:  \: or \: x =\frac{ \sqrt{15} }{5}

We plug this values into the original function to obtain the y-values of the turning points

(   -  \frac{ \sqrt{15} }{5}  , \frac{1}{125} ( 6 \sqrt{15}  +750)) \:and \:  (0, - 6) \: and\: (   \frac{ \sqrt{15} }{5}  , \frac{1}{125} ( - 6 \sqrt{15}  +750))

We now use the second derivative test to determine the absolute maximum minimum on the interval [-1,1]

f''(x) = 20 {x}^{3}  - 6x

f''( -  \frac{ \sqrt{15} }{5} ) \:   <  \: 0

Hence

(   -  \frac{ \sqrt{15} }{5}  , \frac{1}{125} ( 6 \sqrt{15}  + 750))

is a maximum point.

f''( \frac{ \sqrt{15} }{5} ) \:    >  \: 0

Hence

(     \frac{ \sqrt{15} }{5}  , \frac{1}{125} (- 6 \sqrt{15}  + 750))

is a minimum point.

f''(0) \: =\: 0

Hence (0,-6) is a point of inflexion

4 0
3 years ago
What’s the product of (-3)(-1)
Vlad1618 [11]

Answer:

-4

Step-by-step explanation:

negative plus a negative means add

You add the number then keep the negative sign

6 0
3 years ago
PLEASE HELP ME!!!!!!
Nata [24]

9514 1404 393

Answer:

  vertex: (2, -3.2)

  axis of symmetry: x = 2

  zeros: x=0, x=4

  formula for axis of symmetry:

  • x = <x-coordinate of vertex>
  • x = -b/(2a) . . . . . . . where the quadratic is ax^2 +bx +c
  • x = average of zeros, (z1 +z2)/2

Step-by-step explanation:

a) The vertex x-coordinate is halfway between the zeros, so is x = (0+4)/2 = 2. It is where the graph has a turning point.

The vertex y-coordinate is the low point of this graph. It is not on a grid line, so we can only guess at its value. I choose to call it -3.2.

The vertex is (2, -3.2).

__

b) The axis of symmetry is the vertical line through the vertex. The constant in its equation is the x-coordinate of the vertex:

  x = 2

__

c) The zeros of the function are where the function crosses the x-axis. These are marked on the graph with red dots. The zeros are x=0 and x=4.

__

d) When the quadratic is written in standard form, ax^2 +bx +c, the equation of the axis of symmetry is ...

  x = -b/(2a) . . . . . perhaps this is the formula you're being asked for (?)

When there is no equation, the axis of symmetry can be found from the graph a couple of ways. One is to identify the x-coordinate of the vertex.

  x = <x-coordinate of the vertex>

Another is to average the zeros, since they are symmetrical about the axis of symmetry.

  x = average of zeros = (z1 +z2)/2

If the quadratic is written in vertex form, the vertex coordinate is the constant in the equation for the axis of symmetry.

  y = a(x -h)^2 +k . . . . . quadratic with vertex (h, k)

  x = h . . . . . . equation of axis of symmetry

8 0
2 years ago
Angles X and Y are congruent. Imported Asset and Imported Asset . Find the degree measure of angle X.
Sphinxa [80]
You can use a diffrent kind of ruler for math then you could find the answer.
8 0
3 years ago
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