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4 years ago

1) 125 kg to g

Chemistry

2 answers:

Vlada [557]4 years ago

8 0

Answer:

1) 125000g

2) 0.54m

3)0.728hm

4)The second, symbol s

5)kilogram (kg)

hope this helped :) brainliest?

Masteriza [31]4 years ago

6 0

Answer:

1) 125000g2) 0.54m3)0.728hm4) The second, symbol s5)kilogram (kg)

Explanation:

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Annette [7]

Answer:

Explanation:

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4 years ago

Given that the mass of an electron is 5.486×10−4amu, and the mass of a proton is 1.007 amu, calculate how many times heavier a p

Lana71 [14]

Divide the mass of the proton by the mass of the electron.

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4 years ago

50cm3 of 1 mol/dm3 HCl at 30°C was mixed with 50cm3 of 1mol/dm3 NaOH at 30°C in a styrofoam calorimeter. The temperature of the

trapecia [35]

Answer:

-21 kJ·mol⁻¹

Explanation:

Data:

H₃O⁺ + OH⁻ ⟶ 2H₂O

V/mL: 50 50

c/mol·dm⁻³: 1.0 1.0

ΔT = 4.5 °C

C = 4.184 J·°C⁻¹g⁻¹

C_cal = 50 J·°C⁻¹

Calculations:

(a) Moles of acid

$\text{Moles of acid} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}\\\\\text{Moles of base} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}$

So, we have 0.050 mol of reaction

(b) Volume of solution

V = 50 dm³ + 50 dm³ = 100 dm³

(c) Mass of solution

$\text{Mass of solution} = \text{100 dm}^{3} \times \dfrac{\text{1.00 g}}{\text{1 dm}^{3}} = \text{100 g}$

(d) Calorimetry

There are three energy flows in this reaction.

q₁ = heat from reaction

q₂ = heat to warm the water

q₃ = heat to warm the calorimeter

q₁ + q₂ + q₃ = 0

nΔH + mCΔT + C_calΔT = 0

0.050ΔH + 100×4.184×4.5 + 50×4.5 = 0

0.050ΔH + 1883 + 225 = 0

0.050ΔH + 2108 = 0

0.050ΔH = -2108

ΔH = -2108/0.0500

= -42 000 J/mol

= -42 kJ/mol

This is the heat of reaction for the formation of 2 mol of water

The heat of reaction for the formation of mol of water is -21 kJ·mol⁻¹.

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3 years ago

As a storm from moves in, you notice that a column of mercury in a barometer rises to 736 mm. (a) Determine the air pressure. (b

sesenic [268]

Answer:

The air pressure is 9.8 *10^4 pa

The water will rise to a height of 10.0 meter

Explanation:

Step 1: Data given

As a storm from moves in, you notice that a column of mercury in a barometer rises to 736 mm.

Step 2: Calculate the air pressure

The Pressure against the mercury column = h*d*g = 0.736 * 13593 * 9.81 = 9.8 * 10^4 Pa

Step 3: Calculate the height of the water

Let the Pressure the water column for same pressure is h meter : -

9.8 * 10^4 = h*d*g

=>9.8*10^4 = h*1000*9.81

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The water will rise to a height of 10.0 meter

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3 years ago