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Assoli18 [71]
3 years ago
12

1. Approximately how long does the

Chemistry
2 answers:
GenaCL600 [577]3 years ago
8 0

Answer:

about 29.5 days

Explanation:

so yes about a month

d1i1m1o1n [39]3 years ago
3 0

Answer:

i think its a month

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If a sample has 25% parent and 75% daughter, how many halflifes have gone by?
Anit [1.1K]

Answer:

Two half lives.

Explanation:

It is known that the decay of isotopes and radioactive material obeys first order kinetics.

Also, it is clear that in first order decay the half-life time is independent of the initial concentration.

That means for a sample 100% to decay to 50 % it will take one half-life, and to decay the remaining 50% to 25% it will take another half-life.

So, for a sample has 25% parent and 75% daughter it will have two half-lives.

6 0
3 years ago
Which statement about atoms and molecules is
Pavel [41]

Elements always exist as pair of atoms called molecules .

Explanation:-

  • The material which has only one types of similar atoms called element .
  • Ex:-Sodium,Carbon etc
8 0
3 years ago
Read 2 more answers
Help me please Great answer will get more points for the correct answers Please giveing 50 Points
WARRIOR [948]
What is the question ❓
4 0
2 years ago
Read 2 more answers
Determine the number of atom in 5.0 moles in SI
Alex

Answer: 3.01 x 10^24 atoms

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of SI = 6.02 x 10^23 atoms

5.0 moles = Z atoms

To get the value of Z, cross multiply:

(Z atoms x 1 mole) = (6.02 x 10^23 atoms x 5.0 moles)

Z atoms•1 mole = 30.1 x 10^23 atoms•moles

Divide both sides by 1 mole

Z atoms•1 mole / 1 mole = 30.1 x 10^23 atoms•moles / 1 mole

Z = 30.1 x 10^23 atoms

[Place Z in standard form

So, Z = 3.01 x 10^24 atoms]

Thus, there are 3.01 x 10^24 atoms in 5.0 moles in SI

5 0
3 years ago
A una mezcla de 300g, formada con 60% P/P de Hierro y 40% P/P de Arena, se le adicionan 135g de Cobre y 2,77g de Aluminio. ¿Cuál
Svetllana [295]

Answer:

\%P/P_{hierro}=41.1\%\\\\\%P/P_{arena}=24.4\%\\\\\%P/P_{cobre}=30.8\%\\\\\%P/P_{aluminio}=0.6\%

Explanation:

¡Hola!

En este caso, dado que estamos tratando con problem sobre porcentaje peso/peso de hierro, arena, cobre y aluminio, primero debemos calcular la masa inicial de estos dos primeros en la mezcla original de acuerdo con:

m_{hierro}=300g*0.60=180g\\\\m_{arena}=300*0.40=120g

Ahora si podemos calcular la masa de la mezcla final como la suma de las masas de todos los constituyentes de la mezcla:

m_T=180g+120g+135g+2.77g=437.77g

Finalmente, podemos calcular los porcentajes P/P como se muestra a continuación:

\%P/P_{hierro}=\frac{180g}{437.77g} *100\%=41.1\%\\\\\%P/P_{arena}=\frac{120g}{437.77g} *100\%=24.4\%\\\\\%P/P_{cobre}=\frac{135g}{437.77g} *100\%=30.8\%\\\\\%P/P_{aluminio}=\frac{g}{437.77g} *100\%=0.6\%

¡Saludos!

5 0
2 years ago
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