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3 years ago

What is the oxidation number of nitrogen in hno2?

1 answer:

5 0

To solve for the problem above, note that the given compound is not charged which indicates that the sum of the oxidation numbers of atoms present is zero. The oxidation number of H is +1 and that of O is -2. Let x be the oxidation number of N and the generated equation is,

+1 + x + (-2)(2) = 0

From the equation the value of x is 3. Therefore, the oxidation number of N is 3.

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What would happen if you tried to cut a sheet of aluminum foil in half over and over again?

kodGreya [7K]

Answer:

Its properties remain unchanged as it is undergoing physical changes.

Explanation:

Hello.

In this case, since aluminum foil is made up of aluminum leaves having a 0.2-mm thick it is widely known that is deformed when wrinkled due to its tiny average thick. Moreover, when cut half over and over again smaller pieces are obtained every time it is done. Nevertheless, even when its shape and size can be modified via physical actions, its properties remain unchanged because cutting is a physical change which is not affecting its chemical composition.

Best regards.

7 0

3 years ago

How do the organelles within the cell allow life to occur?

spayn [35]

Answer:

There are two types of proteins: structural proteins and enzymes. Cell organelles must work together to carry out protein synthesis, utilize proteins within the cell, and transport them out of the cell.

5 0

3 years ago

32,500 joules are used to boil a sample of water at its melting point what is the mass of the water?

Ivenika [448]

Answer:

43.18 gm

Explanation:

Heat of fusion of water at 0° C is 334 j/gm

then you have to heat the water to boiling point (100 C)

specific heat of water is 4.186 j/g-c

x = grams of water

x ( 334 + 4.186 (100) ) = 32500

x = 43.18 gm

3 0

2 years ago

A sample of natural rubber (200.0 g) is vulcanized, with the complete consumption of 4.8 g of sulfur. Natural rubber is a polyme

nasty-shy [4]

Answer: 1.3% many crosslinks as isoprene units,

Explanation:

Given:

mass pf natural rubber= 200.0g

mass of sulphur = 4.8g

molar mass of sulphur =32g/mol

molar mass of isoprene = C5H8=( 12x5) +(1x8)= 68g/mol

Solution: we first find no of moles present in each using

no of moles = $\frac{mass}{molarmass}$

Isoprene: 200.0g x [1mole / 68g] = 2.94moles.

Sulfur: 4.8g x [1mole / 32g] x [1 mole crosslinks / 4 moles S] = 0.0375 moles crosslinks.

to find % crosslinked units, we have

0.0375 / 2.94 = 1.3% as many crosslinks as isoprene units,

3 0

3 years ago

How many molecules of co2 are in a 500. 0 ml container at 780 mm hg and 135°c? 8. 76 × 1021 molecules 9. 23 × 1021 molecules 5.

Aloiza [94]

ok we have to use the formula PV=nRT

p=Pressure (must be converted to atm)= 780 mmHg

1 amt= 760 mmHg use this as a conversion factor

780 mmHg (1 atm/760 mmHg)= 1.026

V= Volume= 5.00 mL = o.5 L

n=number of moles which we have to find first

R= 0.0821

T(convert to Kelvins by adding 273.15 to the celsius temperature)= 135 C + 273.15= 408.15 k

Now plug in->

(1.026 atm)(o.5 L)= n(0.0821)(408.15 K)

(1.026 atm)(0.5 L)= n(33.509115)

(0.513)= n(33.509115)

n(number of moles)= 0.01532 mol

Now we have to convert to moles using Avagodro's number which states that 1 mol = 6.022 x 10^23 molecules or atoms

So 0.01532 mol (6.022 x 10^23 number of molesules)/ (1 mol) = 9.225704 x 10^21 = 9.226 x 10^21 colecules

Step 2

You must transfer pressure into pascals, 780 mm Hg = 103991 Pa

135*C = 408.15 k

then from the equation pV = nRt

n = pV / RT (T in Kelvins, V in M^3)

n = 103991 x 500 x 10^-6 / (8.314 x 408.15)= 0.015322 moles of N2

1 mol of everything is 6.022 x 10^23 particles, so 0.15322 moles is 0.15322 x 6.022 x 10^23 = 9.2269084 x 10^21 molecules

Explanation:

Hope this helps :)

5 0

2 years ago