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olya-2409 [2.1K]
3 years ago
12

To what volume will you have to dilute 60.0 mL of a 9 M HCl solution to

Chemistry
1 answer:
Alex17521 [72]3 years ago
8 0

Answer:

1542.85\ \text{mL}

Explanation:

V_1 = Volume of HCl = 60 mL

C_1 = Initial concentration of HCl = 9 M

C_2 = Final concetration of HCl = 0.35 M

V_2 = Volume to be diluted

We have the relation

\dfrac{C_1}{C_2}=\dfrac{V_2}{V_1}\\\Rightarrow \dfrac{9}{0.35}=\dfrac{V_2}{60}\\\Rightarrow V_2=\dfrac{9}{0.35}\times 60\\\Rightarrow V_2=1542.85\ \text{mL}

The required volume is 1542.85\ \text{mL}.

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