Predict, using Boyle’s Law, what will happen to a balloon that an ocean diver takes to a pressure of 202 kPa (normal atmospheric
1 answer:
Explanation:
Balloon that an ocean diver takes to a pressure of 202 k Pa will get reduced in size that is the volume of the balloon will get reduced. This is because pressure and volume of the gas are inversely related to each other.
According to Boyle's law: The pressure of the gas is inversely proportional to the volume occupied by the gas at constant temperature(in Kelvins).
(At constant temperature)
The pressure beneath the sea is 202 kPa and the atmospheric pressure is 101.3 kPa . This increase in pressure will result in decrease in volume occupied by the gas inside the balloon with decrease in size of a balloon. Hence, the size of the balloon will get reduced at 202 kPa (under sea).
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Explanation : Given,
Mass of AgO = 900 mg = 900000 g
conversion used : (1 mg = 1000 g)
Molar mass of AgO = 124 g/mole
Molarity of AgO =
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
Now put all the given values in this formula, we get the active mass of urea.
Therefore, the volume of solution will be,