<span>UV gel enhancements rely on ingredients from the monomer liquid and polymer powder chemical family. The chemicals from the polymer powder family </span><span>can absorb and retain extremely large amounts of a liquid relative to their own mass. Water-absorbing polymers, </span>can absorb aqueous solutions through hydrogen bonding with water molecules.
NH4I (aq) + KOH (aq) in chemical equation gives
NH4I (aq) + KOH (aq) = KI (aq) + H2O(l) + NH3 (l)
Ki is in aqueous state H2o is in liquid state while NH3 is in liquid state
from the equation above 1 mole of NH4I (aq) react with 1 mole of KOH(aq) to form 1mole of KI(aq) , 1mole of H2O(l) and 1 Mole of NH3(l)
Answer:
(a) ₁₉K: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹
(b) ₁₀Ne: 1s² 2s² 2p⁶
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(a) 3
(b) 6
(c) 7
Explanation:
We can state the ground-state electron configuration for each element following Aufbau's principle.
(a) ₁₉K: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹
(b) ₁₀Ne: 1s² 2s² 2p⁶
Second part
(a) Al belongs to Group 13 in the Periodic Table. It has 13-10=3 electrons in the valence shell.
(b) O belongs to Group 16 in the Periodic Table. It has 16-10=6 electrons in the valence shell.
(c) F belongs to Group 17 in the Periodic Table. It has 17-10=7 electrons in the valence shell.
Answer:
116.1 a.m.u.
It is not likely that RCOOH is the pentanoic acid
Explanation:
Let's consider the generic neutralization between NaOH and a monoprotic carboxylic acid.
RCOOH(aq) + NaOH(aq) ⇒ RCOONa(aq) + H₂O(l)
The molar ratio of RCOOH to NaOH is 1:1. The moles of RCOOH are:
The molar mass of RCOOH is:
Thus, the molecular weight is 116.1 a.m.u.
Pentanoic acid has the formula C₅H₁₀O₂ with a molecular weight of 102.1 a.m.u. So, it is not likely that RCOOH is the pentanoic acid.
Answer: these are the values of density that complete the table
Sample density
A 1024
B 1027
C 1026
D 1025
E 1028
Procedure: take the values of temperature and salinity for each sample given in the table, and enter the graph to read the corresponding density value.
1) Sample A: temp = 21°C, salinity = 34%
Locate the value 34 on the horizontal axis (salinity axis), move vertically upward until reaching the level of 21 for the vertical axis, read the value of the density on the curve that passes through the point (34, 21). That value is
density = 1024 g/cm^3.
That is the value to copy on the table.
2) Sample B: temp = 11°C, salinity =35 %
Locate the value 35 on the horizontal axis (salinity axis), move
vertically upward until reaching the level of 11 for the vertical axis,
read the value of the density on the curve that passes through the point
(35, 11). That value is
density = 1027 g/cm^3.
That is the value to copy on the table.
3) Sample C: temp = 12°C, salinity = 34%
Locate the value 34 on the horizontal axis (salinity axis), move
vertically upward until reaching the level of 12 for the vertical axis,
read the value of the density on the curve that passes through the point
(34, 12). That value is
density = 1026 g/cm^3.
That is the value to copy on the table.
4) Sample D: temp = 19°C, salinity = 35%
Locate the value 35 on the horizontal axis (salinity axis), move
vertically upward until reaching the level of 19 for the vertical axis,
read the value of the density on the curve that passes through the point
(35, 19). That value is
density = 1025 g/cm^3.
That is the value to copy on the table.
5) Sample E: temp = 3°C, salinity = 35%
Locate the value 35 on the horizontal axis (salinity axis), move
vertically upward until reaching the level of 3 for the vertical axis,
read the value of the density on the curve that passes through the point
(35, 3). That value is
density = 1028 g/cm^3.
That is the value to copy on the table.
