URGENT!!! What is the concentration in moles per litre of a solution that contains 7.68 g of H2SO4 in 150.0 mL of water?

Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample

goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=2:2=1:1$

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=3:3=1:1$

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.

4 0

3 years ago

Which type of bonding is characterized by overlapping orbitals that allow outer electrons of atoms to move about freely througho

Sonja [21]

Answer:

D metallic

Explanation:

The chemical bonding which rises from electrostatic attractive force between the conduction electrons and the positively charged metal ions is called metallic bonding.

<u>It is sharing of the free electrons among the structure of the positively charged ions which are known as cations. </u>

<u>In this type of bonding, these free electrons freely move in the crystal mattice of the metal. </u>

The bonding accounts for properties of metals, such as ductility, strength, electrical and thermal conductivity and resistivity and luster.

6 0

3 years ago

Elements with similar properties are located

Nataly [62]

Those elements with similar properties are in the same column.

4 0

3 years ago

1,5,25,125 what’s the pattern rule and extend by 3 more numbers

nika2105 [10]

For the first one the pattern is multiply the previous number by five as you see 1 x 5 = 5 and so on. To keep adding to it you would do

125 x 5 = 625 625 x 5 = 3125 3125 x 5 = 15625

Now for the second one the pattern is divide the previous number by three as you can see 2187 / 3 = 729 and so on. To keep going you would

81 / 3 = 27 27 / 3 = 9 9 / 3 = 3

I hope this helps you and if you have anymore questions i'll be glad to answer them.

4 0

3 years ago

Please help, need asap, just tell me where they go

Lostsunrise [7]

Answer:

1 to 2 3 to 6

Explanation:

5 0

3 years ago