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vova2212 [387]
3 years ago
15

4 -12 36 -108 324 what's the rule

Mathematics
1 answer:
balandron [24]3 years ago
6 0
Hello,
u_{1}=4\\
u_{2}=4*3=12\\
u_{3}=4*3^2=36\\
u_{4}=4*3^3=108\\
...\\

\boxed{u_{n}=4*{n-1}}\\
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a rectangular swimming pool is 6ft deep. one side of the pool is 2.5 times longer than the other. the amount of water needed to
Sav [38]

6 x 12 x 30 is your answer


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3 years ago
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kykrilka [37]

Answer:

24.   -2l+6

Step-by-step explanation:


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4 years ago
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Find the dimensions of a rectangle with area 512 m2 whose perimeter is as small as possible. (If both values are the same number
Masja [62]

Answer:

<h2>√512 by √512 </h2>

Step-by-step explanation:

Length the length and breadth of the rectangle be x and y.

Area of the rectangle A = Length * breadth

Perimeter P = 2(Length + Breadth)

A = xy and P = 2(x+y)

If the area of the rectangle is 512m², then 512 = xy

x = 512/y

Substituting x = 512/y into the formula for calculating the perimeter;

P = 2(512/y + y)

P = 1024/y + 2y

To get the value of y, we will set dP/dy to zero and solve.

dP/dy = -1024y⁻² + 2

-1024y⁻² + 2 = 0

-1024y⁻² = -2

512y⁻² = 1

y⁻² = 1/512

1/y² = 1/512

y²  = 512

y = √512 m

On testing for minimum, we must know that the perimeter is at the minimum when y = √512

From xy = 512

x(√512) = 512

x = 512/√512

On rationalizing, x = 512/√512 * √512 /√512

x = 512√512 /512

x = √512 m

Hence, the dimensions of a rectangle is √512 m  by √512 m

5 0
4 years ago
Help never learned this!!
musickatia [10]

Answer: A and only A

Step-by-step explanation:

r/3+5<or=8

r/3<or=3

r<or=9

8 0
3 years ago
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Find the measure of angleq, the smallest angle in a triangle whose sides have lengths 4, 5, and 6. round the measure to the near
Pavlova-9 [17]

The measure of the ∠Q = 41°

By law of cosines:

a law in trigonometry: the square of a side of a plane triangle equals the sum of the squares of the remaining sides minus twice the product of those sides and the cosine of the angle between them.

Which can we stated as:

{q}^2 = {p}^2 + {r}^2 - 2prcos(Q)\\{4}^2 = {6}^2 + {5}^2 - 2*6*5*cos(Q)\\\\

solving equation using normal algebra:

60cos(Q) = 36 + 25 - 16

60 cos(Q) = 45

cos(Q) = 45/60

cos(Q) = 3/4

Q = {cos}^{-1} (\frac{3}{4})\\

Thus, Q = 41°

Hence, the measure of the smallest angle in a triangle whose sides have lengths 4, 5, and 6. ∠Q is 41°.

To learn more about Finding angles visit:

brainly.com/question/3067469

#SPJ4

5 0
2 years ago
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