Distance<-------------300--------------><-------------------x----------------->
⊕---------------------------------⊕--------------------------------------⊕ Express Freight Overtaking point
Speed 55 speed 30
Let x be the distance travelled by Freight until the point of overtaking
Time = Distance/Speed, then:
Time (freight) = Distance (fright)/Speed (freight) And
Time (Express) = Distance (Express)/Speed (Express).
Now plug in the relative number:
Time (freight) = x/30 and Time (express) = (x+300)/55. But note that both times are equal, then:
x/30 = (x+300)/55 OR (x÷30 = (x+300)÷55) [Answer C]
Now let's find the distance x. Cross multiplication;
55x= 30(300+x) →55x = 9,000 + 30x
55x - 30x = 9,000 → 25x = 9,000 and x = 9,000/25 = 360 miles
Time needed for Freight to travel 360 m = 360/30= 12 Hours
Time needed for Express to travel (300+360) m = 660/55= 12 Hours
As you see, it's the same time of 12 hours
Don't forget that Distance = Speed x time or time = Distance/Speed, etc.
1st. Find the pattern
Pattern is dividing by 2.
24/2=12
12/2=6
6/2=3
Answer:
The fraction of wood used for horizontal support is
.
Step-by-step explanation:
Assume that the total piece of wood is of length 1.
It is provided that Talia used
of the piece of wood for the base of he project.
She use
of the piece of wood for the for the vertical support.
The remaining wood she used for horizontal support.
The amount of wood used for horizontal support can be computed by the subtracting the amount of wood used for base of the project and vertical support form 1.
Compute the amount of wood used for horizontal support as follows:

Thus, the fraction of wood used for horizontal support is
.
First we need to count the total number scores. This can be done from the stem and leaf plot. The total number of scores are 19. The total number of values is odd, so the median position will be:

Thus the 10th score is the median score for the class of Mr. Robert. The 10th score from the stem and leaf plot is 81.
Thus 81 is the median score of Mr. Robert's Class.