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3 years ago

What does it mean to amortize a loan?

Mathematics

1 answer:

Oksana_A [137]3 years ago

7 0

Answer:

D. Bring a loan to an end.

Step-by-step explanation:

An amortized loan is a loan with scheduled payment plan which covers both the principal and interest, the interest expense for the period is paid first before the remainder of the payment reduces the principal. It is a way of brining a loan to an end.

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The fictitious state of Aribraska has a graduated state income tax.

earnstyle [38]

Answer:

Your answer choice is correct: the range 15,000–40,000

Step-by-step explanation:

Above income of 15,000 and below income of 40,000, the problem statement tells us the tax rate is 5%. If income amount is represented by x, then .05x is the amount of the tax (subject to the credits offered by the graduated scale). The term 0.05x in the question tells you the applicable range is 15,000 ≤ x ≤ 40,000.

If 15,000 were taxed at the 5% rate, the tax amount would be $750. Instead, the tax amount on that income is 3% of 15,000, or $450—a tax that is $300 less than 0.05x. Hence in the range 15,000–40,000, the tax computation is ...

... f(x) = 0.05x -300 . . . . . for 15,000 ≤ x ≤ 40,000

_____

<em>Above 40,000</em>

At the middle income tax rate, $40,000 would have a tax of ...

... 0.05×40000 -300 = 1700

At 7%, $40,000 would have a tax of

... 0.07×40000 = 2800

Then the actual tax on amounts above $40,000 is $1100 less than 7% of the income.

... f(x) = 0.07x -1100 . . . . . for x ≥ 40,000

7 0

3 years ago

Read 2 more answers

Please hellp

ankoles [38]

Answer:

he needs 3 bags i did this test

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The question is on the picture

Ghella [55]

Answer:6/10

Step-by-step explanation:

hope youdo well

7 0

3 years ago

(NEED HELP ASAP)

EleoNora [17]

Answer:

The correct option is 1 and 4 are correct.

Step-by-step explanation:

The dilation is the enlargement and comparison of a figure according to the scale factor from the given center of dilation.

The rule DO,2(x,y)(2x,2y) express the dilation with factor 2 and the center of dilation is origin. It shows the enlargement of the triangle. The sides of image is twice of the preimage.

In dilation the corresponding angles remains same and the corresponding sides are equal.

$\angle P=\angle P'$

$\angle PQR=\angle Q'$

$\angle R=\angle P'QQ'$

$PR=P'Q$

$PQ=P'Q'$

$RQ=QQ'$

Therefore option 1 and 4 are correct.

5 0

3 years ago

Read 2 more answers

Calculate the pH of a buffer solution made by mixing 300 mL of 0.2 M acetic acid, CH3COOH, and 200 mL of 0.3 M of its salt sodiu

Lesechka [4]

Answer:

Approximately $4.75$ .

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of $\rm CH_3COOH$ and $\rm CH_3COO^{-}$ are equal.

${\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}$

Since $\rm CH_3COONa$ is a salt soluble in water. Once in water, it would readily ionize to give $\rm CH_3COO^{-}$ and $\rm Na^{+}$ ions.

Assume that the $\rm CH_3COOH$ and $\rm CH_3COO^{-}$ ions in this solution did not disintegrate at all. The solution would contain:

$0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol$ of $\rm CH_3COOH$ , and

$0.06\; \rm mol$ of $\rm CH_3COO^{-}$ from $0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol$ of $\rm CH_3COONa$ .

Accordingly, the concentration of $\rm CH_3COOH$ and $\rm CH_3COO^{-}$ would be:

$\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}$ .

$\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}$ .

In other words, in this buffer solution, the initial concentration of the weak acid $\rm CH_3COOH$ is the same as that of its conjugate base, $\rm CH_3COO^{-}$ .

Hence, once in equilibrium, the $\rm pH$ of this buffer solution would be the same as the ${\rm pK}_{a}$ of $\rm CH_3COOH$ .

Calculate the ${\rm pK}_{a}$ of $\rm CH_3COOH$ from its ${\rm K}_{a}$ :

$\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}$ .

7 0

3 years ago