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muminat
3 years ago
5

Jimmy loaded three bags of sand into his wheelbarrow. The bags weighed 24/12 lbs, 32/35 lbs, and 44/18 lbs. The total amount of

sand in the wheelbarrow is
Mathematics
1 answer:
sasho [114]3 years ago
3 0
The correct answer is 5 113/315
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Annita, Gary, and Tara all run races. Annita has 7 less than 4 times the number of race medals as Tara. Gary has 13 more than 2
harkovskaia [24]

Answer:

4 t - 7  = 2 t+ 13  is the required equation.

The number of race medals Tara has is t = 20 medals.

Step-by-step explanation:

Let the number of medals Tara has = t medals

So, the number of medal Anita has  = 4( Medals of Tara) - 7

= 4t - 7

And the number of medals Gary has = 2 times (Medals of Tara) + 13

= 2(t)  + 13  = 2t + 13

Now, Annita and Gary has same number of medals.

⇒  4t - 7  = 2t+ 13

or, 4t - 2t  = 7 + 13

⇒ 2t  = 20

⇒ t = 20/2 = 10

or t = 10

Hence, the number of race medals Tara has is t = 20 medals

6 0
3 years ago
Joey earned $10 of every car he washed. If he earned $190 how many cars did he wash?
mars1129 [50]

Answer:

19

Step-by-step explanation:

190/10= 19

6 0
3 years ago
Read 2 more answers
Tell me the answer on this to lazy at least am honest ​
luda_lava [24]

Answer:

reflection

Step-by-step explanation:

it goes against the y axis

3 0
3 years ago
Read 2 more answers
12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests
Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that p = 0.12.

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so n = 18

This probability is:

P = P(X = 0) + P(X = 1)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002

P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458

So

P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460

There is a 34.60% probability that 0 or 1 of them is nearsighted.

5 0
3 years ago
Yolanda has finished 45 percent of her homework and she has finished 27 problems. How many problems was Yolanda assigned
masya89 [10]
If 45 percent of the homework is only 27 problems, she needs to figure out this:

What is 47 percent of 60?
              or
47% x 60

Which is 27. 

So, Yolanda was assigned 60 problems.


6 0
3 years ago
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