When the base of a triangle is fixed at 2.218 millimeters, the area will be 0.1098 mm².
<h3>What will the area be?</h3>
It should be noted that the area of a triangle is calculated as:
Area of triangle = (1/2)×base×height
= (1/2) × 2.218 mm × 0.099 mm
= 1.109 mm × 0.099 mm
= 0.109791 mm²
≈ 0.1098 mm²
Therefore, the <em>area</em> is 0.1098 mm².
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The base of a triangle is fixed at 2.218 millimeters. Determine the number of
significant figures of the area of the triangle with each given height of 0.099mm.
Answer:
Step-by-step explanation:
Hey there!!!
According to the question,
Angle P is three less than twice less of an angle Q.
Then, let angle Q be x then angle P is 2x-3.
Now, it has also given that they are supplementary angle.
We know that the sum of supplementary angle is 180°.
Therefore, x+ 2x - 3°=180°.
Or, 3x = 180°-3°
Or, x = 177°/3
Therefore the measure of angle Q is 59° and P is 2×59°-3°= 121°.
Hope it helps....
20 and 8 make a product of 160
and their difference is 12
I'm really not that sure too. Maybe it exists. I'm still learning calculus.
