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3 years ago

Help me on this??? Will mark as Brainiest

Mathematics

2 answers:

lara [203]3 years ago

7 0

Answer:

first answer is 7 square root 2, second is 39, third is 5.36487494991.

Step-by-step explanation:

1st answer: its a right triangle with both sides as 45 degrees no shorter legs or longer legs. so both opp and adj legs are equal to 7. 7 times 7 plus 7 times 7 is 98 so square it into radical form and get 7 square root 2. second is 39 because of the 3,4,5. 15 36 and 39 are ratios of the rule. Third is 5.45454545... because make a triangle with a right triangle properties. name the hyp variable A. Find each angle which is 90, 56 ( the top of the triangle where plane is ) and 34 ( at the boat place ). You use Sine with 34 which is (0.55919290347...). This is equal to 3 km over A. Change the form and turn it into A=3 divided by 0.55...) which is 5.36487494991.

Leviafan [203]3 years ago

3 0

Answer:11 and 12 is g and g and answer 13 is 5.36487494991

Step-by-step explanation:

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Question 4

laiz [17]

Answer:

I just solved a question similar to this

Let's understand it

It's saying she got 660 or it is that her weekly pay is 660

So now let weekly pay which is P be 660

Hence the formulae is given

It's 480 + 18 (h – 30) = 660

Now its just boring calculation

If you mark it brainleist I will do the calculation for you wink wink

Never mind

480 + 18 (h – 30) = 660

18 (h – 30) = 660-480

18 (h – 30) = 120

(h – 30) = 120/18

(h – 30) = 6.6

h = 6.6+30

h= 36.6

So dam the Judy lady worked for 36.6 hours

5 0

2 years ago

What is the period of f(x)

Stells [14]

Step-by-step explanation:

The period of f(x) is π.

To calculate the period using the formula derived from the basic sine and cosine equations. The period for function y = A sin (B a – c) and y = A cos ( B a – c ) is equal to 2πB radians. The reciprocal of the period of a function is equal to its frequency.

8 0

2 years ago

Read 2 more answers

The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation of 1.4. The distributio

posledela

Answer:

Approximate probability that $\overline{X}$ is less than 2 = 0.1515

Step-by-step explanation:

Given -

Mean $(\nu )$ = 2.2

Standard deviation $(\sigma )$ = 1.4

Sample size ( n ) = 52

Let $\overline{X}$ be the mean of accidents per week at the intersection during one year (52 weeks) .

probability that $\overline{X}$ is less than 2 =

$P(\overline{X}< 2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}< \frac{2 - 2.2 }{\frac{1.4}{\sqrt{52}}})$ Putting $(Z =\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}})$