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3 years ago

There is two questions!

Mathematics

1 answer:

Nataly_w [17]3 years ago

3 0

Answer:

1. parallelogram, quadrilateral, rectangle, square

2. A

Step-by-step explanation:

1. Not a rhombus/trapezoid

2. None of the other choices make sense

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Exterior Angles and Isosceles Triangles

Ad libitum [116K]

Step-by-step explanation:

this is not an isoceles triangle.

anyway, we need to remember 2 things :

1. the sum of all angles in a triangle is always 180°.

2. the sum of all angles around a single point on a line is 360° (as this point wound be the center of an invisible circle). and as the line cuts this circle in half, the angles on one side of the line around this point is therefore 180°.

so, the internal angle Q is then

180 = 50 + 55 + Q

Q = 180 - 50 - 55 = 180 - 105 = 75°

the exterior angle x at Q is then

180 = Q + x = 75 + x

x = 180 - 75 = 105°

3 0

2 years ago

Read 2 more answers

Evaluate the integral Integral ∫ from (1,2,3 ) to (5, 7,-2 ) y dx + x dy + 4 dz by finding parametric equations for the line seg

n200080 [17]

$\vec F(x,y,z)=y\,\vec\imath+x\,\vec\jmath+3\,\vec k$

is conservative if there is a scalar function $f(x,y,z)$ such that $\nabla f=\vec F$ . This would require

$\dfrac{\partial f}{\partial x}=y$

$\dfrac{\partial f}{\partial y}=x$

$\dfrac{\partial f}{\partial z}=3$

(or perhaps the last partial derivative should be 4 to match up with the integral?)

From these equations we find

$f(x,y,z)=xy+g(y,z)$

$\dfrac{\partial f}{\partial y}=x=x+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$f(x,y,z)=xy+h(z)$

$\dfrac{\partial f}{\partial z}=3=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=3z+C$

$f(x,y,z)=xy+3z+C$

so $\vec F$ is indeed conservative, and the gradient theorem (a.k.a. fundamental theorem of calculus for line integrals) applies. The value of the line integral depends only the endpoints:

$\displaystyle\int_{(1,2,3)}^{(5,7,-2)}y\,\mathrm dx+x\,\mathrm dy+3\,\mathrm dz=\int_{(1,2,3)}^{(5,7,-2)}\nabla f(x,y,z)\cdot\mathrm d\vec r$

$=f(5,7,-2)-f(1,2,3)=\boxed{18}$

8 0

3 years ago

Again, please help. i dont know any of this

Levart [38]

$\textrm {Cylinder volume :}$

$\mathrm {Volume = \pi r^{2}{h}}$

$\mathrm {Volume = 3.14 \times (\frac{4}{2})^{2} \times 3}$

$\mathrm {Volume = 3.14 \times 12}$

$\mathrm {Volume = 37.68cm^{3}}$

$\textrm {Rectangular prism volume :}$

$\mathrm {Volume = length \times width \times height}$

$\mathrm {Volume = 6 \times 5 \times 7}$

$\mathrm {Volume = 30 \times 7}$

$\mathrm {Volume = 210cm^{3}}$

$\textrm {Total volume of composite figure :}$

$\textrm {Volume of cylinder + volume of rectangular prism}$

$\mathrm {37.68 + 210}$

$\mathrm {247.68cm^{3}}$

4 0

1 year ago

Read 2 more answers

Pls help me, and do not send links. Thanks

ipn [44]

i uploaded a vid on this here

https://www.you tube.com/watch?v=dQw4w9WgXcQ

8 0

3 years ago

A newsletter publisher believes that above 78 % of their readers own a personal computer. Is there sufficient evidence at the 0.

GalinKa [24]

Answer:

$h_{0}$ : p= .78

$h_{a}$ : p > .78

Step-by-step explanation:

Determining the null and alternate hypotheses of a scenario require several components. The first is if one should use p or mu. This depends on if they are assessing a proportion or a mean, since the publisher states a percentage, you know that they are asking for a proportion, and therefore should use p. Next, they will need to assess what value to use for the hypothesis statements, here only .78 is provided and therefore should be used in both. Finally, it is time to add in the comparison symbols, the null hypothesis always uses an equals sign so it therefore becomes:

$h_{0}$ : p= .78

The alternate hypothesis then needs to consider if the researchers claim that the new proportion is greater, fewer, or different. In this case it is greater as they think that the ownership is above 78%, so a greater than sign would be used and the final statement would be:

$h_{a}$ : p > .78

5 0

3 years ago