Answer:
4.895 m
Explanation:
at the maximum height, the vertical speed will be zero.
u=9.80 m/s
Since it is travelling upwards, a =-9.81 m/s^2
At max height, v= 0 m/s
Therefore by the formula, v^2 = u^2 + 2ax, calculate x
0 = 9.80^2 + 2 (-9.81) x
x = 96.04/19.62
x = 4.895 m
Answer:
The pressure inside the bubble is 666.67
Solution:
As per the question:
Radius, R =
Now,
Given that the surface tension of the wall is the same as that of soapy water.
The air trapped inside the bubble exerts pressure on the soap bubble which is given by:
Gauge Pressure, P =
Also, the surface tension of the soapy water,
To calculate the pressure inside the alveolus:
Answer:
.25 m/s
Explanation:
We shall use the law of conservation of momentum . We do not use law of conservation of mechanical energy because in such cases there is loss of energy.
Momentum = mass x velocity
Initial momentum of arrow and block
= .15 x 30 +0 = 4.5 J
If final velocity of block be V
Total final momentum of both arrow and block
= .15 x 25 + 3 V
= 3.75 +3V
So
3.75 + 3 V = 4.5
V = .25 m/s
Answer:
a) 28.1 m/s
b) 27.2 m
Explanation:
a)
Consider the motion of the marble in downward direction taking down direction as positive
v₀ = initial velocity = 5 m/s
v = final velocity as it hits the ground = ?
a = acceleration = 9.8 m/s²
d = vertical height traveled = 39 m
Using the equation
v² = v₀² + 2 a d
v² = 5² + 2 (9.8) (39)
v = 28.1 m/s
b)
t = time of travel = 1.90 s
y = vertical distance traveled
Using the equation
y = v₀ t + (0.5) a t²
y = (5)(1.90) + (0.5) (9.8) (1.90)²
y = 27.2 m