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Flauer [41]
3 years ago
12

A 0.50-kg block attached to an ideal spring with a spring constant of 80 N/m oscillates on a horizontal frictionless surface. Th

e total mechanical energy is 25 J. The maximum speed of the block is:
Physics
1 answer:
wolverine [178]3 years ago
6 0

Answer:

Explanation:

easy way

when system is all kinetic energy, velocity is at a maximum

E = ½mv²

v = √(2E/m) = √(2(25)/0.5) = √100 = 10 m/s

harder way

ω = √(k/m) = √(80/0.5) = √160 rad/s

When the system is entirely spring potential, the amplitude A is

E = ½kA²

A = √(2E/k) = √(2(25)/80) = 0.790569... = 0.79 m

maximum velocity is ωΑ = 0.79√160 = 10 m/s

You might be interested in
A block of mass m = 2.0 kg lies on a rough ramp that is inclined at an angle θ = 20oto the horizontal. A force F of magnitude 5.
Marina86 [1]

Answer:

a) 0.64 b) 2.17m/s^2 c) 8.668joules

Explanation:

The block was on the ramp, the ramp was inclined at 20degree. A force of 5N was acting horizontal to the but not parallel to the ramp,

Frictional force = horizontal component of the weight of the block along the ramp + the applied force since the block was just about move

Frictional force = mgsin20o + 5N = 6.71+5N = 11.71

The force of normal = the vertical component of the weight of the block =mgcos20o = 18.44

Coefficient of static friction = 11.71/18.44= 0.64

Remember that g = acceleration due to gravity (9.81m/s^2) and m = mass (2kg)

b) coefficient of kinetic friction = frictional force/ normal force

Fr = 0.4* mgcos 20o = 7.375N

F due to motion = ma = total force - frictional force

Ma = 11.71 - 7.375 = 4.335

a= 4.335/2(mass of the block) = 2.17m/s^2

C) work done = net force *distance = 4.335*2= 8.67Joules

8 0
3 years ago
As a horse finishes its trot around the corral, it slows from 4m/s to a stop in 3
german
As a horse finishes its trot around the corral, it slows from 4m/s to a stop in 3
seconds. Calculate the acceleration of the horse.
Can anybody help ?
8 0
3 years ago
A fly wheel with a diameter of 1.20m is rotating at an angular speed of 200 Rev/min
gladu [14]

Answer:a) 20.944rad/s (b) 12.57m/s (c) 800rev/min²

Explanation:

5 0
3 years ago
1 point
marta [7]

Answer:

Let, R be the resistance of the heater wire. Since, two heater wires are of equal length their resistance is also same.

Hence, for series combination of resistances,

R

s

=2R

And for parallel combination of resistances,

R

p

=

2

R

Now, heat produced when they first connected in series is

H

s

=

R

s

V

2

where, V is voltage supplied to the heater.

H

s

=

2R

V

2

.....................................(1)

heat produced when they first connected in series is

H

p

=

R

p

V

2

H

p

=

2

R

V

2

H

p

=

R

2V

2

............................................(2)

From (1) and (2), we get

H

p

H

s

=

R

2V

2

2R

V

2

⇒

H

p

H

s

=

4

1

7 0
3 years ago
A monkey increases its gravitational potential energy by climbing to the top of a tree. What happens to that potential energy if
Sedaia [141]
It would decrease by half
6 0
3 years ago
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