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4 years ago

A 2-kg bowling ball rolls at a speed of 10 m/s on the ground.

1 answer:

8 0

It's kinetic energy as the ball the ball isn't raised above the ground it does not have any gravitational potential energy.
To find the kinetic energy of the ball you will have to use the formula:
KE=0.5 x m x v squared
m being mass and v being velocity
so the calculation is:
0.5 x 2 x 10 x 10= 100J

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The potential energy of a particle experiencing a certain kind of force is given by U(x) = 2x + 8 x measured in joules (J), for

masha68 [24]

Answer:

Explanation:

Given

Potential Energy of a particle is given by $U(x)=2x+\frac{8}{x}$

For minimum or maximum Potential Energy differentiate U(x) w.r.t x

$\frac{\mathrm{d} U}{\mathrm{d} x}=2-\frac{8}{x^2}$

putting $\frac{\mathrm{d} }{\mathrm{d} x}=0$

$2-\frac{8}{x^2}=0$

$x^2=\frac{8}{2}$

$x^2=4$

$x=\sqrt{4}=\pm 2$

To know minimum value check $\frac{\mathrm{d^2} U}{\mathrm{d} x^2}$

at x=-2

$\frac{\mathrm{d^2} U}{\mathrm{d} x^2}=\frac{16}{x^3}=-\frac{16}{8}=-2$

so at x=-2 potential energy is minimum $U=-8\ J$

8 0

3 years ago

9 m/s to a total stop. what is the objects acceleration

MAVERICK [17]

We would need to know the time it took to slow to a stop.

5 0

3 years ago

An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. Its image is 16.0 cm in front of the mirro

svet-max [94.6K]

We can rearrange the mirror equation before plugging our values in.
1/p = 1/f - 1/q.
1/p = 1/10cm - 1/40cm
1/p = 4/40cm - 1/40cm = 3/40cm
40cm=3p <-- cross multiplication
13.33cm = p

Now that we have the value of p, we can plug it into the magnification equation.

M=-16/13.33=1.2
1.2=h'/8cm
9.6=h'

So the height of the image produced by the mirror is 9.6cm.

6 0

3 years ago

A bird can fly 25 km/h. How long does it take to fly 3.5km?

monitta

The equation of motion that we can use in this case is:

t = d / v

where t is time, d is distance, v is velocity

Therefore calculating for t:

t = 3.5 km / (25 km / h)

<span>t = 0.14 h = 8.4 minutes</span>

6 0

3 years ago

A string of mass m is under tension, and the speed of a wave in the string is v. what will be the speed of a wave in the string

horsena [70]

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4 years ago