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kogti [31]
3 years ago
10

Helpppppppppppp!!!!!!!!

Chemistry
1 answer:
atroni [7]3 years ago
6 0

The answer is D.) +0.34 V

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On the addition of HI
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Answer:

CH_3-CH(I)-CH(CH_3)-CH_3

I-CH_2-CH_2-CH(CH_3)-CH_3

Explanation:

Given the compound CH_2=CH-CH(CH_3)-CH_3

The steps of reaction:

HI \longrightarrow H^+ + I^-

CH_2=CH-CH(CH_3)-CH_3 + H^+ \longrightarrow CH_3-CH^+-CH(CH_3)-CH_3

<u>But this intermediate product has a resonance: </u>

CH_3-CH^+-CH(CH_3)-CH_3 \longleftrightarrow C^+H_2-CH2-CH(CH_3)-CH_3

The reaction with I-

CH_3-CH^+-CH(CH_3)-CH_3 + I^- \longrightarrow CH_3-CH(I)-CH(CH_3)-CH_3

C^+H_2-CH2-CH(CH_3)-CH_3 + I^- \longrightarrow I-CH_2-CH_2-CH(CH_3)-CH_3

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3 years ago
How does the number of reactants in a double-displacement reaction
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In a typical double displacement reaction, you would have a total of two products (AB + CD —> AD + BC).
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Atoms and molecules are constantly in motion. The more energy the atom or molecule contains, the faster they move about. In whic
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2 years ago
Problem 12.002 the molar analysis of a gas mixture at 30°c, 2 bar is 40% n2, 50% co2, 10% ch4. determine
andreev551 [17]
The problem is incomplete. However, there can only be two probable questions for this problem. First, you can be asked the individual partial pressures of each gas. Second, you can be asked the volume occupied by each gas. I can answer both cases for you.

1.

Let's assume ideal gas.
Pressure for N₂: 2 bar*0.4 = 0.8 bar
Pressure for CO₂: 2 bar*0.5 = 1 bar
Pressure for CH₄: 2 bar*0.1 = 0.2 bar

2. For the volume, let's find the total volume first.

V = nRT/P = (1 mol)(8.314 J/mol-K)(30 +273 K)/(2 bar*10⁵ Pa/1 bar)
V = 0.0126 m³
Hence,
Volume for N₂: 0.0126 bar*0.4 = 0.00504 m³
Volume for CO₂: 0.0126*0.5 = 0.0063 m³
Volume for CH₄: 0.0126*0.1 = 0.00126 m³
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