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kogti [31]
3 years ago
5

Adam is trying to identify a solid. He places a small amount of the substance in an acid solution and observes whether or not a

reaction takes place. This test is based on a _______ property. A. biological B. chemical C. radical D. physical
Chemistry
2 answers:
garri49 [273]3 years ago
5 0

Answer: The correct answer is option (B).

Explanation:

In order to identify the solid Adam is followed chemical technique or procedure to identify the unknown solid reacts with acid or not.

A chemical test is a qualitative and quantitative procedure performed to identify or quantify a chemical compound or a substance.

Where as physical test is a qualitative and quantitative procedure which deals physical properties of substance like: density, temperature etc.

Biological test deals is qualitative and qualitative test which deals with testing of biological properties of the substance like: Diatoms(unicellular microorganisms) present in water bodies.

Radical test is a qualitative and quantitative procedure which is done to identify and quantify the radicals present in given substance or a chemical compound.For Example: Qualitative and quantitative analysis of anion cation.



EleoNora [17]3 years ago
4 0
Chemical property because he is dealing with acid, (a chemical)
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A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu
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Answer: The final temperature of nickel and water is  25.2^{o}C.

Explanation:

The given data is as follows.

   Mass of water, m = 55.0 g,

  Initial temp, (t_{i}) = 23^{o}C,      

  Final temp, (t_{f}) = ?,

  Specific heat of water = 4.184 J/g^{o}C,      

Now, we will calculate the heat energy as follows.

           q = mS \Delta t

              = 55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)

Also,

    mass of Ni, m = 15.0 g,

   Initial temperature, t_{i} = 100^{o}C,

   Final temperature, t_{f} = ?

 Specific heat of nickel = 0.444 J/g^{o}C

Hence, we will calculate the heat energy as follows.

          q = mS \Delta t

             = 15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)      

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

              q_{water}(gain) = -q_{alloy}(lost)

55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C) = -(15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C))

       t_{f} = \frac{25.9^{o}C}{1.029}

                 = 25.2^{o}C

Thus, we can conclude that the final temperature of nickel and water is  25.2^{o}C.

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lana66690 [7]

Answer:

need more so we can answer

Explanation:

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