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maxonik [38]
2 years ago
10

PLEASE HELP!!!! i give a lot of points

Chemistry
1 answer:
hammer [34]2 years ago
5 0
spdcowihdej 1
aodnwofrh 2
sixj3
dosprwpr3
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Which of the following lists stars in order of increasing size?
Citrus2011 [14]
B. Or D. Im confused they both make sence
3 0
2 years ago
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What is the total number of elements in group 17 that are gases at room temperature and standard pressure?
White raven [17]

Answer:

Only to elements are gases at room temperature and standard pressure.

Fluorine and chlorine.

Explanation:

The group 17 is called halogen.

There are five elements in halogen group.

All halogens required one electrons to complete the octet and to get the noble gas electronic configuration.

All halogen elements have seven valance electrons.

Halogen elements:

Fluorine, chlorine, Bromine, iodine and astatine

Fluorine is gas at room temperature which s 25°C and standard pressure which is 1 atm.

It is present in the from of F₂.

Chlorine is also gas at room temperature and standard pressure.

It is present in the from of Cl₂.

The bromine is liquid under these condition.

Iodine and astatine are solids.

As we move down the group their melting and boiling points increases.

4 0
3 years ago
How many moles are in 325mL of 1.25M (NH4)2SO4
mote1985 [20]

Answer:

n_{solute}=0.406mol(NH_4)_2SO_4

Explanation:

Hello,

In this case, since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in liters:

M=\frac{n_{solute}}{V_{solution}}

For the given volume and molarity, we solve for the moles of ammonium sulfate (solute) as shown below:

n_{solute}=M*V_{solution}=1.25\frac{mol}{L}*325mL*\frac{1L}{1000mL}  \\\\n_{solute}=0.406mol(NH_4)_2SO_4

Best regards.

4 0
3 years ago
36.8 g of CuSO4(s) was added to water to prepare a 2.00 L solution. What is the
Yuki888 [10]

Answer:

Option D. 0.115 M

Explanation:

The following data were obtained from the question:

Mass of CuSO4 = 36.8 g

Volume of solution = 2 L

Molar mass of CuSO4 = 159.62 g/mol

Molarity of CuSO4 =..?

Next, we shall determine the number of mole in 36.8 g of CuSO4.

This can be obtained as shown below:

Mass of CuSO4 = 36.8 g

Molar mass of CuSO4 = 159.62 g/mol

Mole of CuSO4 =.?

Mole = mass /Molar mass

Mole of CuSO4 = 36.8 / 159.62

Mole of CuSO4 = 0.23 mole

Finally, we shall determine the molarity of the CuSO4 solution as illustrated below:

Mole of CuSO4 = 0.23 mole

Volume of solution = 2 L

Molarity of CuSO4 =..?

Molarity = mole /Volume

Molarity of CuSO4 = 0.23 / 2

Molarity of CuSO4 = 0.115 M

Therefore, the molarity of the CuSO4 solution is 0.115 M.

5 0
3 years ago
How many moles of CF4 could be made from 456g of F?
lord [1]

Answer:

132 moles dhhdhsysushdgdgsgsgsgsgsv

3 0
2 years ago
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