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3 years ago

Which two processes turn layers of loose sediment into hard sedimentary rock? (ASAP)

Chemistry

1 answer:

kvasek [131]3 years ago

6 0

Answer:

compaction and cementation

Explanation:

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A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg

Brut [27]

Answer: $1.0\times 10^2g$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

$K_f$ = freezing point constant = $3.96^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}$

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

$7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}$

$x=1.0\times 10^2g$

Thus $1.0\times 10^2g$ urea was dissolved.

8 0

4 years ago

Mountain ranges are the result of many different

Effectus [21]

Answer:

Mountain ranges are formed by a variety of geological processes, but most of the significant ones on Earth are the result of plate tectonics. Mountain ranges are also found on many planetary mass objects in the Solar System and are likely a feature of most terrestrial planets.

7 0

3 years ago

Read 2 more answers

The reaction shown below has a positive enthalpy change and a negative entropy change. 2C (s) + 2H2 (g) yields C2H4 (g) Which of

Drupady [299]

Answer is: <span>The reaction will not be spontaneous at any temperature.

</span>

<span>Gibbs free energy (G) determines if reaction will proceed spontaneously.
ΔG = ΔH - T·ΔS.
ΔG - changes in Gibbs free energy.
ΔH - changes in enthalpy.
ΔS - changes in entropy.
T is temperature in Kelvins.
When ΔS < 0 (negative entropy change) and ΔH > 0 (endothermic reaction), the process is never spontaneous (ΔG> 0).</span>

5 0

3 years ago

True or false. adding more neutrons to a neutrally charged atom will not change the charge

san4es73 [151]

The statement is true.

6 0

4 years ago

Arrange the following molecules in order of increasing bond polarity (highest bond polarity at the bottom):

Tom [10]

NF3– 0.94– third
NCl3–0.12– second
NBr3–0.08– first
CF4–1.43– fourth

NBr3—NCl3—NF3—CF4
Lowest. Highest

4 0

3 years ago