I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])
Answer:
9
15
24
33
Step-by-step explanation:
I hope this right
<u>Answer:</u>
C. Left-handed: 48, Right-handed: 504
D. Left-handed: 30, Right-handed: 315
<u>Step-by-step explanation:</u>
We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.
Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.
Ratio of right handed to left handed students at East Middle School = 
Checking for ratios of the given options:
A. 
B. 
C. 
D. 
E. 
Therefore, the possible numbers of left-handed and right-handed students at West Junior High could be C. Left-handed: 48, Right-handed: 504 and D. Left-handed: 30, Right-handed: 315.
10 to the sixth power = 1,000,000
1,000,000 ÷ 2 3/5 = 384615.384615
ANSWER : 384615.384615