Answer:
Distance =√(x₁ - y₁)²+ (x₂ - y₂)² = √97 = 9.85
Step-by-step explanation:
The Matrix X and Y could also be referred to as vectors in Rⁿ dimensions.
if Vector X = ( x₁ , x₂) and Vector Y = (y₁ , y₂)
then, Distance (X-Y) = ||X-Y|| = √(x₁ - y₁)²+ (x₂ - y₂)²
where, x₁ = 8, x₂ = -5 and y₁ = -1 , y₂ = -9
Distance = √(8 - (-1))²+ (-5 - (-9))² = √9² + 4² =√97 = 9.85
(1 - 2x)⁴
(1 - 2x)(1 - 2x)(1 - 2x)(1 - 2x)
[1(1 - 2x) - 2x(1 - 2x)][1(1 - 2x) - 2x(1 - 2x)]
[1(1) - 1(2x) - 2x(1) - 2x(-2x)][1(1) - 1(2x) - 2x(1) - 2x(-2x)]
(1 - 2x - 2x + 4x²)(1 - 2x - 2x + 4x²)
(1 - 4x + 4x²)(1 - 4x + 4x²)
1(1 - 4x + 4x²) - 4x(1 - 4x + 4x²) + 4x²(1 - 4x + 4x²)
1(1) - 1(4x) + 1(4x²) - 4x(1) - 4x(-4x) - 4x(4x²) + 4x²(1) - 4x²(4x) + 4x²(4x²)
1 - 4x + 4x² - 4x + 16x² - 16x³ + 4x² - 16x³ + 16x⁴
1 - 4x - 4x + 4x² + 16x² + 4x² - 16x³ - 16x³ + 16x⁴
1 - 8x + 24x² - 32x³ + 16x⁴
The percentage of 15% of 9 is 60% (I think)
Given:
Sides of triangles in the options.
To find:
Which could NOT be the lengths of the sides of a triangle.
Solution:
Condition for triangle:
Sum of two smaller sides of a triangle must be greater than the longest side.
In option A,
Sides 5 in, 5 in, 5 in are the lengths of the sides of a triangle.
In option B,
Sides 10 cm, 15 cm, 20 cm are the lengths of the sides of a triangle.
In option C,
Sides 3 in, 4 in, 5 in are the lengths of the sides of a triangle.
In option D,
Since, the sum of two smaller sides is less than the longest side, therefore the sides 8 ft, 15 ft, 5 ft are not the lengths of the sides of a triangle.
Therefore, the correct option is D.
Answer:
if you mean find OS, then:
OS = 42
Step-by-step explanation:
if you mean find OS, then:
8x-51 = 3x-6
5x = 45
x = 9
OS = 2(3x-6)
OS = 6x-12
substitute for x
OS = 6(9)-12 =42
