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3 years ago

Pless help I want to hang my self

Mathematics

1 answer:

Strike441 [17]3 years ago

8 0

The answer is 27, but I might be wrong

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3 hours 20 minutes - 1 hour 48 minuets <br> A. 2.12<br> B. 2.52<br> C. 1.32<br> D. 1.53

chubhunter [2.5K]

3 hours and 20 minutes minus 1 hour and 48 minuets equals an hour and 32 minutes. There are 60 minuets in an hour and 60 divided by 32 is 0.53. This means that your final answer is:
D. 1.53

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3 years ago

What is 7 x 5/8 because I’m so lost

svetoff [14.1K]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 4.375

I hope this helped!

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2 years ago

Read 2 more answers

Segment Addition Postulate Task Cards

Mandarinka [93]

Oppor it plenty no flow
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3 years ago

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Shalnov [3]

Answer:

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Step-by-step explanation:

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2 years ago

In a sample of 41 temperature readings taken from the freezer of a restaurant, the mean is 29.7 degrees and the population stand

yKpoI14uk [10]

Answer: $=(29.1596\text{ degrees},\ 30.2404\text{ degrees})$

Step-by-step explanation:

Given: Sample size: n = 41

Sample mean $\overline{x}= 29.7$ degrees

Population standard deviation $\sigma=2.7$ degrees

Confidence level (c) = 80% =0.80

Significance level (a) = 1- c = 1-0.80 = 0.20

z-score for 80% confidence level : z = 1.2816 [from z-table]

Confidence level for population mean :-

$\overline{x}\pm z\dfrac{\sigma}{\sqrt{n}}$

$=29.7\pm ( 1.2816)\dfrac{2.7}{\sqrt{41}}$

$=29.7\pm ( 1.2816)\dfrac{2.7}{6.403124}$

$=29.7\pm ( 1.2816)(0.42167)$

$=29.7\pm 0.5404$

$=(29.7-0.5404,\ 29.7+0.5404)$

$=(29.1596,\ 30.2404)$

Hence, 80% confidence interval for the temperatures in the freezer $=(29.1596\text{ degrees},\ 30.2404\text{ degrees})$

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2 years ago