Answer:
8 $10 notes
Step-by-step explanation:
I started by working it backwards. $93-$3 equals $90. So we have three of our 13 notes. We need ten more. Well the most $10 notes we can have is 8. if we had 8 $10 notes that would give us $80. $90-$80=10. We can take ten and divide it by five so we have 2 $5 notes.
So in total he would have 8 $10 notes, 2 $5 notes, and $3 one dollar notes which adds up to 13 notes
The correct answer is C
Sigma Notation is when we take all of the whole numbers between the starting point (which can be found as the number under the sigma sign) and the end number (which can be found above the sigma sign). Therefore, we will add together all of the values of 3k + 2 for when k is equal to all of the numbers between 2 and 7. So, let's evaluate each one first.
When k = 2
3(2) + 2 = 8
When k = 3
3(3) + 2 = 11
When k = 4
3(4) + 2 = 14
When k = 5
3(5) + 2 = 17
When k = 6
3(6) + 2 = 20
When k = 7
3(7) + 2 = 23
So we know we have the following.
8 + 11 + 14 + 17 + 20 + 23
Now for the number after the comma, we are just looking for the answer of them all added together. So the final answer should be
8 + 11 + 14 + 17 + 20 + 23, 93
Keeping in mind that, there are 12 months in a year, therefore, 7 months is really just 7/12 of a year.
Answer:
7n is greater than or equal to 21
t4+10
Step-by-step explanation:
