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Julli [10]
3 years ago
9

How do you "undo" a squared number or variable?

Mathematics
2 answers:
ANEK [815]3 years ago
8 0
Roots" (or "radicals") are the "opposite" operation of applying exponents<span>; you can "undo" a power with a radical, and a radical can "undo" a power. For instance, if you square </span>2<span>, you get </span>4<span>, and if you "take the square root of </span>4<span>", you get </span>2<span>; if you square </span>3<span>, you get </span>9<span>, and if you "take the square root of </span>9<span>", you get </span>3: <span>  </span>
vodomira [7]3 years ago
3 0
Dividing a said number by itself should get rid of its square
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I thought of a two-digit number. The unit digit of my number is a prime number, and the tens digit is four times as big as the u
sergiy2304 [10]
<h3>Answer:  82</h3>

====================================================

Explanation:

Let A be the tens digit and B be the units digit

We can write the number as AB. So if A = 9 and B = 2 for instance, then the number is AB = 92. Keep in mind I'm not multiplying A and B here.

"The unit digit is a prime" means B could be any of these values {2,3,5,7}. We only list the single digit primes. The value 1 is not prime.

Now multiply each of those items by 4

4*2 = 8

4*3 = 12

4*5 = 20

4*7 = 28

Of those results, only 4*2 = 8 leads to a single digit answer.

This must mean that A = 8 and B = 2

Therefore the number is AB = 82.

4 0
2 years ago
Which expression is equivalent to 5^6
timama [110]

Answer:

  • Option B

Step-by-step explanation:

  • A. 36 × 6 × 6 × 6 = 6²⁺¹⁺¹⁺¹ = 6⁵                                incorrect
  • B. 125 × 125 = 5³ × 5³ = 5³⁺³= 5⁶                             correct
  • C. 6 × 5                                                                    incorrect
  • D. 25 × 5 × 5 × 5 = 5² × 5 × 5 × 5 = 5²⁺¹⁺¹⁺¹ = 5⁵    incorrect
8 0
2 years ago
Read 2 more answers
Please help
Mice21 [21]

Answer:

Option A:

y = 3*(x - 5)^2 - 4

Step-by-step explanation:

For a quadratic equation:

y = a*x^2 + b*x + c

with the vertex (h, k), we can rewrite the function as:

such that:

h = -b/2*a

y = a*(x - h)^2 + k

Here we have the function:

y = 3*x^2 - 30*x + 71

the x-value of the vertex will be:

h = -(-30)/(2*3) = 30/6 = 5

And k is given by:

k = y(5) = 3*(5)^2 - 30*5 + 71 = -4

Then the vertex is:

(5, - 4)

And we can rewrite the equation in the vertex form as:

y = 3*(x - 5)^2 + (-4)

y = 3*(x - 5)^2 - 4

Then the correct option is A.

7 0
3 years ago
In a function of the form y= ax^2 +bx + c which of the following is always true? A. If a is positive, the parabola will have a m
GuDViN [60]
A is always true

If a is negative the parabola wil have a minimum value
4 0
3 years ago
1. What is the money taken from your paycheck that is paid to the state and federal government?
mariarad [96]
Taxes is the correct answer hope this helps :)
3 0
2 years ago
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