Answer:
T' 
Step-by-step explanation:
See the diagram attached.
This is a unit circle having a radius (r) = 1 unit.
So, the length of the circumference of the circle will be 2πr = 2π units.
Now, the point on the circle at a distance of x along the arc from P is T
.
Therefore, the point on the circle at a distance of 2π - x along the arc from P will be T' , where, T' is the image of point T, when reflected over the x-axis. (Answer)
Looking at the problem I think the answers are C, D, AND E
Answer:
An equation for the absolute value that represents the midpoint of 10 and 15 would be (10 + 15)/2 = 12.5
Part A
(3x)^2*x^4
(3x)*(3x)*x^4 .... expand out (3x)^2
(3*3)*(x*x*x^4)
9x^6
Answer: 9x^6
============================================
Part B
It appears that Tonya forgot to square the 3 term and had this as her steps
(3x)^2*x^4
3x^2*x^4
3x^(2*4)
3x^8
Which is incorrect as the answer in part A indicates.
Not only is the '3' part wrong, but also the exponent of 8. Instead of multiplying the exponents, she should have added them.
The rule is a^b*a^c = a^(b+c). In this case, a = x, b = 2 and c = 4.
So x^2*x^4 = x^(2+4) = x^6
Answer:
833/1000
Step-by-step explanation:
