Multiply 1/9 by 9r and 3 = r + 1/3
then distribute the - sign = -r -4
and solve the problem r + 1/3 - r - 4 = 1/3-4 = -11/3
30% = 30/100
= 0.3
Now if we say that x% of a number is y then it actually means that x% multiplied by that number would be equal to y, thus:
30%*56 = 0.3*56
= 16.8
So 2 real solutions
just write 2 factors and expand
(x-3)(x-4)=0
x^2-7x+12=0
discriminant is when you have b^2-4ac
so subsitute
ax^2+bx+c=0
a=1
b=-7
c=12
-7^2-4(1)(12)
49-48=1
discriminant=1
one real solution would be
(x-1)(x-1)=0
x^2-2x+1=0
discriminant=-2^2-4(1)(1)=4-4=0
discriminant=0
no real solutions has the discriminant less than zero
let's say that b=1 and c=20 and a=1
basically, we need a set of numbers where b^2 is less than 4acso
1^2-4(1)(20)=1-80=-79
then we subsitute
x^2+x+20=0
Answer:
yeah happy new year but your answer is D
Step-by-step explanation:
I'm good at math
Answer:
3.2 × 10²
im not really good at this but hope it helps.
