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3 years ago

The value of y varies directly with x, and when x=8, y=2. Write an equation to represent the direct variation.

Mathematics

2 answers:

sdas [7]3 years ago

7 0

Answer: y=1/4x

Step-by-step explanation:

Direct variation looks like this y=kx divide 8 and 2 that will give you 4. Since there is no numerator add a one at the top.

Citrus2011 [14]3 years ago

6 0

Answer:

y=1/4x

Step-by-step explanation:

a direct variation equation is y=kx. if y=1/4x, then when x=8, y=2.

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3 years ago

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Which shows the correct solution to the inequality StartFraction 7 over 10 EndFraction greater-than-or-equal-to 1 and StartFract

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Answer:

The correct answer is p $\geq$ $\frac{74}{80}$

Step-by-step explanation:

An inequality compares two quantities unlike an equality. An inequality is written with either a greater than ( > ) or lower than ( < ) or greater than equal to ( ) or less than equal to ( ) signs. We solve the above given inequality to find the solutions of the unknown p. An inequality reverses if and only if we we multiply both sides with a negative quantity. Addition or subtraction does not change the sign in the inequality.

$\frac{7}{10} \geq 1 + \frac{5}{8} + p\\\\\frac{7}{10} \geq \frac{13}{8} + p\\\\\frac{7}{10} - \frac{13}{8} \geq p\\\\\frac{-74}{80} \geq p\\p \leq \frac{-74}{80} \\p\geq \frac{74}{80}$

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3 years ago

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The given line segment has a midpoint at (3, 1).

Katena32 [7]

Answer:

$y=\frac{1}{3}x$

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through $(x_1,y_1)\ and\ (x_2,y_2)$ is:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$ .

Therefore the line passing through (2, 4) and (4, -2) has an equation:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10$

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

$m_1m_2=-1$ .

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

$m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}$

Since it is the perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

$\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x$