(6y - 11)(6y + 11) = ay
² - b |use (a - b)(a + b) = a² - b²
(6y)² - 11² =ay² - b
36y² - 121 = ay² - b |add b to both sides
ay² = 36y² - 121 + b |divide both sides by y² ≠ 0
a = (36y² - 121 + b)/y²
Answer:
yes
Step-by-step explanation:
Answer:
The probability of getting a factor of 12 on a fair dice is 5/6 or approximately 83%.
Step-by-step explanation:
Probability is expressed as a fraction where the denominator is the total number of outcomes and the numerator is the number of desired outcomes. In this case, the desired outcome is any factor of 12. The factors of 12 are the numbers we multiply together to get that number: 1, 2, 3, 4, 6 and 12. Since a fair dice has the total outcomes of either 1, 2, 3, 4, 5 or 6, then the total outcomes is 6 and the possibility that we could roll the desired outcome (factor of 12) is 5, the probability is 5 out of 6 or 5/6, which when divided is approximately 83%.
Answer:
I think it is this because it seems as if It is 2 separate equations.
a.x=9-2y/3
b.x=3+y/3
