The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Using V = ⅓[base area×height]
V= ⅓[ (5.5÷4)² × 2.6]
v= ⅓[ 4.92]
v = 1.6m³
Answer:
yes it's a refelction over the line f (C)
Step-by-step explanation:
so c is correct
Answer: Undefined
Step-by-step explanation:
4y+x=12, 2x=24-8y
Isolate x by subtracting 4y
4y+x=12
x=12-4y
Plug the equation for x in to anywhere you see the variable x in the other equation
2(12-4y)=24-8y
Distribute 2
24-8y=24-8y
Get the variables on one side so add 8y (cancels out)
24=24
Can’t solve its undefined
