Answer:
y=-32, 0, -16, -4, 16
Step-by-step explanation:
y=4(-6)-8= -32
y=4(2)-8 = 0
y=4(-2)-8 = -16
y=4(1) -8 = -4
y=4(6) -8= 16
Again, I've attached an image showing the 30-60-90 relationship for triangles. Hopefully this should help as we work through this problem.
For the side adjacent to the 30 degree angle, we know that the side length is . Let's take a look at the given options and see which ones fit.
The options that fit are
and
.
For the side adjacent to the 60 degree angle, we know that the side length is just x. Let's take a look at the given options and see which ones fit.
The options that fit are x and 7.
Finally, the hypotenuse is the longest side of the triangle and its length is equal to 2x.
So, the options that fit are 2x and 14.
Hope this helps! :)
Answer:
Step-by-step explanation:
-6x^2 - x + 4x^2 - 10x + 1 = -2x^2 - 11x + 1
To get p - 9, subtract p2 + 3 from p2 + p - 6.
Since we want just the top 20% applicants and the data is normally distributed, we can use a z-score table to check the z-score that gives this percentage.
The z-score table usually shows the percentage for the values below a certain z-score, but since the whole distribution accounts to 100%, we can do the following.
We want a z* such that:

But, to use a value that is in a z-score table, we do the following:

So, we want a z-score that give a percentage of 80% for the value below it.
Using the z-score table or a z-score calculator, we can see that:
![\begin{gathered} P(zNow that we have the z-score cutoff, we can convert it to the score cutoff by using:[tex]z=\frac{x-\mu}{\sigma}\Longrightarrow x=z\sigma+\mu](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28zNow%20that%20we%20have%20the%20z-score%20cutoff%2C%20we%20can%20convert%20it%20to%20the%20score%20cutoff%20by%20using%3A%5Btex%5Dz%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5CLongrightarrow%20x%3Dz%5Csigma%2B%5Cmu)
Where z is the z-score we have, μ is the mean and σ is the standard deviation, so:

so, the cutoff score is approximately 72.