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STALIN [3.7K]
3 years ago
5

A motorboat travels 165 Kilometers in 5 hours going up stream. It travels 305 kilometers going downstream in the same amount of

time. What is the rate of the boat in still water and what is the rate of the current
Mathematics
1 answer:
Serhud [2]3 years ago
6 0
<h2>Rate of the boat in still water is 47 km/hr and rate of the current is 14 km/hr</h2>

<em><u>Solution:</u></em>

Given that,

A motorboat travels 165 Kilometers in 5 hours going up stream.

It travels 305 kilometers going downstream in the same amount of time

Therefore,

Upstream distance = 165 km

Upstream time = 5 hours

<h3><u>Find upstream speed:</u></h3>

speed = \frac{distance}{time}\\\\speed = \frac{165}{5}\\\\speed = 33

Thus upstream speed is 33 km per hour

Downstream distance = 305 km

Downstream time = 5 hours

<h3><u>Find downstream speed:</u></h3>

speed = \frac{305}{5}\\\\speed = 61

Thus downstream speed is 61 km per hour

<em><u>If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then </u></em>

Speed downstream = u + v km/hr

Speed upstream = u - v km/hr

Therefore,

u + v = 61 ---- eqn 1

u - v = 33 ----- eqn 2

<em><u>Add eqn 1 and eqn 2</u></em>

u + v + u - v = 61 + 33

2u = 94

u = 47

<em><u>Substitute u = 47 in eqn 1</u></em>

47 + v = 61

v = 61 - 47

v = 14

Thus rate of the boat in still water is 47 km/hr and rate of the current is 14 km/hr

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3 years ago
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Answer:

3x^2 + 3  -->  6, 15, 30, 51

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Step-by-step explanation:

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Substitute 1 (the first digit in a sequence) for x.

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